VAIR¯AKU ARGUMENTU FUNKCIJU DIFERENCI¯ALR¯EK¸ INI
VAIR¯AKU ARGUMENTU FUNKCIJU DIFERENCI¯ALR¯EK¸ INI
VAIR¯AKU ARGUMENTU FUNKCIJU DIFERENCI¯ALR¯EK¸ INI
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52 V nodal¸a. UZDEVUMI INDIVIDUĀLAJAM DARBAM<br />
10. f(x; y; z) = ln sin(x − 2y + z<br />
<br />
), M0<br />
4<br />
1; 1<br />
; π<br />
2<br />
11. f(x; y; z) = arcsin (x √ y) − yz 2 , M0(0; 4; 1);<br />
12. f(x; y; z) = x2 + y2 <br />
− 2xy cos z, M0 3; 4; π<br />
<br />
;<br />
2<br />
13. f(x; y; z) = ze − (x2 +y 2 )<br />
2 , M0(0; 0; 1);<br />
z<br />
14. f(x; y; z) =<br />
x4 + y2, M0(2; 3; 25);<br />
15. f(x; y; z) = ln x 3 + 3√ y − z , M0(2; 1; 8).<br />
V Izskaitl¸ot netieˇsā veidā definētas funkcijas parciālo atvasinājumu vērtības<br />
dotajā punktā:<br />
1. x 3 + y 3 + z 3 − 3xyz = 4, M0(2; 1; 1);<br />
2. x 2 + y 2 + z 2 − xy = 2, M0(−1; 0; 1);<br />
3. 3x − 2y + z = xy + 5, M0(2; 1; −1);<br />
4. e z + x + 2y + z = 4, M0(1; 1; 0);<br />
5. x 2 + y 2 + z 2 − z − 4 = 0, M0(1; 1; −1);<br />
<br />
;<br />
6. z 3 + 3xyz + 3y = 7, M0(1; 1; 1);<br />
7. cos 2 x + cos 2 y + cos 2 z = 3<br />
<br />
π 3π π<br />
, M0 ; ; ;<br />
2 4 4 4<br />
8. e z−1 <br />
− 1 = cos x cos y + 1, M0 0; π<br />
<br />
; 1 ;<br />
2<br />
9. x 2 + y 2 + z 2 − 6x = 0, M0(1; 2; 1);<br />
10. xy = z 2 − 1, M0(0; 1; −1);<br />
11. x 2 − 2y 2 + 3z 2 − yz + y = 2, M0(1; 1; 1);<br />
12. x 2 + y 2 + z 2 + 2xz = 5, M0(0; 2; 1);<br />
13. x cos y + y cos z + z cos x = π<br />
,<br />
2<br />
<br />
M0 0; π<br />
<br />
; π ;<br />
2<br />
14. e z − xyz − x + 1 = 0, M0(2; 1; 0);<br />
15. ln z = x + 2y − z + ln 3, M0(1; 1; 3).<br />
VI Uzrakstīt dotās virsmas S pieskarplaknes un normāles vienādojumu<br />
punktā M0(x0; y0; z0):<br />
1. x 2 + y 2 + z 2 + 6z − 4x + 8 = 0, M0(2; 1; −1);<br />
2. x 2 + z 2 − 4y 2 = −2xy, M0(−2; 1; 2);