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deňlik ýerine ýetmeli. Aýdyňlyk üçin ilki başda deňlemäniň derejesi n-san 4-egalyndysyz bölünýän san, ýagnyi = −1 hyýaly birligiň derejeleri üçin:n = 4⋅kdiýip hasap edýäris. (2) deňlemedei4S= 1,i4S+1= ii4S+2= −1i4S+3= −ibolýandygyny hasaba alyp, alarys:⎡⎢a⎢⎣4k⎡+ ⎢a⎢⎣⎛ p ⎞⋅⎜⎟⎝ q ⎠4k−14k⎛ p ⎞⋅⎜⎟⎝ q ⎠− a4k−14k−2− a⎛ p ⎞⋅⎜⎟⎝ q ⎠4k−34k−2⎛ p ⎞⋅⎜⎟⎝ q ⎠+ ... − a4k−32⎛ p ⎞⋅⎜⎟⎝ q ⎠+ ... − a32+ a⎛ p ⎞⋅⎜⎟⎝ q ⎠03⎤⎥ +⎥⎦p⎤+ a1⋅ ⎥ ⋅i= 0.q⎥⎦(3)Kompleks sanyň nula deň bolmagy üçin onuň hakyky we hyýaly bölegindäkiaňlatmalar hem nula deň bolmaly, ýagny:4k4k−2⎛ p ⎞ ⎛ p ⎞⎛ p ⎞a4 k⋅⎜⎟ − a4k 2⋅⎜⎟ + ... − a2⋅⎜⎟ + a0= 0, (4)−⎝ q ⎠ ⎝ q ⎠⎝ q ⎠4k−14k−33a4 k1=⎛ p ⎞ ⎛ p ⎞⎛ p ⎞ p1⋅⎜⎟ − a4k3⋅⎜⎟ + ... − a3⋅⎜⎟ + a ⋅ 0. (5)− −⎝ q ⎠ ⎝ q ⎠⎝ q ⎠ q4k(4) deňlemäniň iki tarapyny hem q4k 1hem q− -e köpeldip, maýdalawjylardan boşadalyň:2-a köpeldip, (5) deňlemäniň iki tarapynya4k4k−222 4k−24ka4 k ⋅ p − a 4k− 2 ⋅ p ⋅q+ ... − a2⋅ p ⋅q+ a0⋅ q = 0, (6)4k−14k−323 4k−44k−2− 1 ⋅ p − a 4k−3⋅ p ⋅q+ ... − a3⋅ p ⋅q+ a1p⋅q0. (7)4 k=(7) deňlikden p-ni ýaýyň daşyna çykaryp alarys:4k−24k−42 4k−44k−2( a ⋅ p − a ⋅ p + ... − a ⋅ p ⋅q+ a ⋅q) ⋅ p 0.4 k−14k−331 =Şertleşişimize görä, p ≠ 0.Diýmek:a4k−24k−42 4k−44k−2− 1 ⋅ p − a 4k−3⋅ p + ... − a3⋅ p ⋅q+ a1⋅q0. (8)4 k=80