Bose-Einstein Condensates in Rotating Traps and Optical ... - BEC
Bose-Einstein Condensates in Rotating Traps and Optical ... - BEC
Bose-Einstein Condensates in Rotating Traps and Optical ... - BEC
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12.2 Uniform case 161<br />
The Bogoliubov amplitudes must comply with the normalization condition<br />
<br />
dz<br />
<br />
dx<br />
<br />
dy |uq,px,py(r)| 2 −|vq,px,py(r)| 2<br />
=1. (12.10)<br />
Eq. (12.1) adquately describes the quantum depletion provided<br />
∆Ntot<br />
Ntot<br />
Otherwise it is necessary to go beyond Bogoliubov theory.<br />
12.2 Uniform case<br />
≪ 1 . (12.11)<br />
At lattice depth s =0, Eq. (12.1) yields the quantum depletion of the weakly <strong>in</strong>teract<strong>in</strong>g<br />
uniform <strong>Bose</strong> gas. In this case the sum <br />
j,q with q belong<strong>in</strong>g to the first Brillou<strong>in</strong> zone can<br />
be replaced by <br />
q with<br />
q = 2π<br />
ν,<br />
L<br />
ν=0, ±1, ±2,... . (12.12)<br />
The correctly normalized Bogoliubov amplitudes are given by<br />
e<br />
uq,px,py(r) =Uq,px,py<br />
i(pxx+pyy)/¯h<br />
L3/2 e iqz , (12.13)<br />
e<br />
vq,px,py(r) =Vq,px,py<br />
i(pxx+pyy)/¯h<br />
L3/2 e iqz ,<br />
with<br />
(12.14)<br />
Uq,px,py =<br />
Vq,px,py =<br />
p2 2m +¯hωuni<br />
<br />
p2¯hωuni 2 2m<br />
p2 2m − ¯hωuni<br />
<br />
p2¯hωuni 2 2m<br />
, (12.15)<br />
, (12.16)<br />
where p2 = p2 x + p2 y +¯h 2 q2 <strong>and</strong> ω is the dispersion relation of the elementary excitations<br />
<br />
p<br />
¯hωuni =<br />
2 <br />
p2 2m 2m +2gn<br />
<br />
. (12.17)<br />
We <strong>in</strong>sert (12.13,12.14) <strong>in</strong>to Eq.(12.1). To obta<strong>in</strong> the result <strong>in</strong> the thermodynamic limit<br />
Ntot, L→∞,n= const. we make use of the cont<strong>in</strong>uum approximation<br />
<br />
→<br />
px,py,q<br />
L3<br />
(2π) 3<br />
1<br />
¯h 2<br />
<br />
dpx<br />
<br />
dpy dq . (12.18)<br />
This leads to<br />
∆Ntot<br />
Ntot<br />
= 1 L<br />
Ntot<br />
3<br />
(2π) 3<br />
1<br />
¯h 2<br />
<br />
dpx dpy dq|Vq,px,py| 2<br />
= 1 L<br />
Ntot<br />
3<br />
(2π) 3<br />
1<br />
¯h 2<br />
∞<br />
4πp<br />
0<br />
2 dp 1<br />
⎡<br />
p<br />
⎣<br />
2<br />
2<br />
4g2n2m +1/2<br />
<br />
p2 4g2n2m (<br />
p2 4g2n2m +1)<br />
⎤<br />
− 1⎦<br />
. (12.19)