15.04.2013 Views

Bose-Einstein Condensates in Rotating Traps and Optical ... - BEC

Bose-Einstein Condensates in Rotating Traps and Optical ... - BEC

Bose-Einstein Condensates in Rotating Traps and Optical ... - BEC

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

70 Stationary states of a <strong>BEC</strong> <strong>in</strong> an optical lattice<br />

ε/ER<br />

12<br />

10<br />

8<br />

6<br />

4<br />

2<br />

0<br />

5 10 15 20 25 30<br />

Figure 6.6: Gap between first <strong>and</strong> second Bloch b<strong>and</strong> of the spectra (6.4) <strong>and</strong> (6.5) at ¯hk = qB<br />

as a function of lattice depth s for gn =0(solid l<strong>in</strong>e) <strong>and</strong> gn =1ER (dashed <strong>and</strong> dashdotted<br />

l<strong>in</strong>es respectively). The dotted l<strong>in</strong>e <strong>in</strong>dicates the value 2 √ sER given by the harmonic<br />

approximation of the potential well.<br />

where ¯hk is the quasimomentum <strong>and</strong> j the b<strong>and</strong> <strong>in</strong>dex. The correspond<strong>in</strong>g energy functional<br />

yields the “energy per particle”<br />

d/2<br />

εj(k, A) =<br />

−d/2<br />

ϕ ∗ <br />

1<br />

jk(z)<br />

Differentiation with respect to A gives<br />

1<br />

¯h<br />

<br />

∂εj(k, A)<br />

∂A<br />

2m (−i¯h∂z +¯hA) 2 + sER s<strong>in</strong> 2 (z)+ 1<br />

2<br />

A=0<br />

s<br />

<br />

2<br />

gnd|ϕjk(z)| ϕjk(z)dz.<br />

(6.12)<br />

= i¯h<br />

d/2 <br />

dz ϕjk∂zϕ<br />

2m −d/2<br />

∗ jk − ϕ ∗ <br />

jk∂zϕjk . (6.13)<br />

It is important that ϕjk need not be differentiated because δε/δϕ =0. The <strong>in</strong>tegr<strong>and</strong> is<br />

Ij(k)/nd where Ij(k) is the current density (6.9). Hence, we have<br />

1<br />

¯h<br />

<br />

∂εj(k, A)<br />

∂A<br />

A=0<br />

= Ij(k)<br />

n<br />

. (6.14)<br />

However, the dependence of ε on A is completely fictional. Due to the gauge <strong>in</strong>variance of<br />

the GP-equation, A can be excluded from the equation by the substitution<br />

φjk = e iAz ϕjk(z,A) =e i(A+k)z ˜ϕjk(z,A) . (6.15)<br />

The function φjk satisfies the usual GP-equation. This means that the energy Bloch b<strong>and</strong>s<br />

for the modified GP-equation (6.10) are the same as for the usual one. However, the function

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!