5003 Lectures - Faculty of Engineering and Applied Science

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E5003 - Ship Structures I 142 © C.G. Daley To get the total solution we need to scale the * problem by λ (we call this the ** problem) and add it to the 'f ' problem. How large is λ ? λ is chosen so that the conditions at the "false" sway support are corrected. If there is no direct force at the false support, (as in the example at left), we want: λF*2x = -F f 2x If there is a direct force at the false support, we would want: λF*2x = F2x - F f 2x
E5003 - Ship Structures I 143 © C.G. Daley Example of MDM with Sway To illustrate the moment distribution method with sway, we will use a problem similar to Example 3 in Topic 13. In this case the problem has a roller on the left, instead of a pin. As a result the frame can sway. To solve the problem we need to split the problem into two component problems. The first problem has sway prevented (by a pin on the left support). The complementary problem has an imposed sway which will create a reaction of opposite magnitude to the first problem. The first problem was solved in Example 3 above. The reaction at the left hand pin was (see pg. 130);
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5003 Lectures - Faculty of Engineering and Applied Science

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