5003 Lectures - Faculty of Engineering and Applied Science
5003 Lectures - Faculty of Engineering and Applied Science
5003 Lectures - Faculty of Engineering and Applied Science
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E<strong>5003</strong> - Ship Structures I 55<br />
© C.G. Daley<br />
This gives us a set <strong>of</strong> station buoyancy forces due to the wave (net <strong>of</strong> still water).<br />
These forces should be in equilibrium (no net vertical force). We can calculate the<br />
moment at midships from either the net effect <strong>of</strong> all forces forward, or all forces aft<br />
(the two moments will balance).<br />
There are other ways to do this kind <strong>of</strong> calculation. 3D cad programs such as Rhino<br />
can be used to find the still water <strong>and</strong> wave bending moments. Assuming that we<br />
have a hull modeled in Rhino, we can find the still water buoyancy forces for the<br />
fore <strong>and</strong> aft halves <strong>of</strong> the vessel by finding the volume <strong>and</strong> location <strong>of</strong> the centroids<br />
<strong>of</strong> the two submerged volumes.<br />
The procedure would be as follows;<br />
1. Produce solid model <strong>of</strong> hull<br />
2. Cut the model at both the centerline <strong>and</strong> waterlines.<br />
3. Find the volumes <strong>and</strong> centroids <strong>of</strong> the two halves.<br />
4. Calculate the buoyant moments about midships.<br />
A similar procedure would determine the wave values. The only difference would be<br />
the need to draw the trochoidal wave as a surface.<br />
The example below shows use <strong>of</strong> Rhino to calculate the Bouyant BM for a large<br />
vessel. The centroids <strong>of</strong> the two half volumes are shown.<br />
BMB = 109,000 x 1.025 x 53.97 (m3 x t/m3 x m = t-m)<br />
= 6,029,798 t-m<br />
or<br />
BMB = 123,000 x 1.025 x 58.58 (m3 x t/m3 x m = t-m)<br />
= 7,385,473 t-m<br />
average: BMB = 6,707,376 t-m (sag)