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On-Site Wastewater Treatment and Disposal Systems - Forced ...

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Step 8: Select proper pump or siphon.<br />

For a pump system, the total pumping head of the network must<br />

be calculated. This is equal to the elevation difference<br />

between the pump <strong>and</strong> the distribution lateral inverts, plus<br />

friction loss in the pipe that delivers the wastewater from the<br />

pump to the network at the required rate, plus the desired<br />

pressure to be maintained in the network (the velocity head is<br />

neglected). A pump is then selected that is able to,discharge<br />

the minimum rate (83 gpm) at the calculated pumping head.<br />

For a siphon system, the siphon discharge pipe must be elevated<br />

above the lateral inverts at a distance equal to the friction<br />

losses <strong>and</strong> velocity head in the pipe that delivers the waste-<br />

water from the siphon to the network at the required rate, plus<br />

the desired pressure to be maintained in the network.<br />

For this example, assume the dosing tank is located 25 ft from<br />

the network inlet, <strong>and</strong> the difference in elevation between the<br />

pump <strong>and</strong> the inverts of the distribution laterals is 5 ft.<br />

a. Pump (assume 3-in. diameter delivery pipe)<br />

1. Friction loss in 3-in. pipe at 83 gpm (from Table 7-14)<br />

Friction loss in 25 ft<br />

= 1.38 + 2 (1.73 - 1.38)<br />

= 1.49 ft/loo ft<br />

= (1.49 flYlO ft) x (25 ft)<br />

= 0.4 ft<br />

2. Elevation Head = 5.0 ft<br />

3. Pressure to be maintained = 2.0<br />

Total pumping head = 7.4 ft<br />

Therefore, a pump capable of delivering at least 83 gpm against<br />

7.4 ft of head is required.<br />

b. Siphon (assume 4-in. diameter delivery pipe)<br />

1. Friction loss in 4-in. pipe at83 gpm (from Table 7-14)<br />

= 0.37 + J-j (0.46 - 0.37)<br />

= 0.4 ft/loo ft<br />

290

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