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Statistical Analysis of Trends in the Red River Over a 45 Year Period

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variance <strong>of</strong> S is computed;<br />

Var(S) =<br />

n(n − 1)(2n + 5)<br />

18<br />

and <strong>the</strong> test statistic Z, is as follows;<br />

When <strong>the</strong>re are tied values,<br />

Var(S) = 1 18<br />

[<br />

⎧<br />

S − 1<br />

, if S > 0;<br />

⎪⎨ [Var(S)]<br />

1/2<br />

Z = 0, if S = 0;<br />

S + 1<br />

⎪⎩ , if S < 0.<br />

[Var(S)]<br />

1/2<br />

n(n − 1)(2n + 5) −<br />

]<br />

g∑<br />

t p (t p − 1)(2t p + 5) ,<br />

where g is <strong>the</strong> number <strong>of</strong> tied groups and t p is <strong>the</strong> number <strong>of</strong> observations <strong>in</strong> <strong>the</strong><br />

pth group<br />

Once Var(S i ) is computed, we pool across <strong>the</strong> K seasons and our test statistic<br />

Z is computed.<br />

p=1<br />

If <strong>the</strong> result <strong>of</strong> <strong>the</strong> test statistic for a one sided test is greater<br />

than 1.6<strong>45</strong> we reject our null hypo<strong>the</strong>sis that no trend exists at <strong>the</strong> 5% level <strong>of</strong><br />

significance.<br />

The seasonal Kendall slope estimator procedure is as follows;<br />

First we compute <strong>in</strong>dividual N i slope estimates for <strong>the</strong> ith season:<br />

Q i = x il − x ik<br />

l − k ,<br />

where x il <strong>the</strong> data for <strong>the</strong> i’th season <strong>of</strong> <strong>the</strong> l’th year and x ik <strong>the</strong> data for <strong>the</strong> i’th<br />

season <strong>of</strong> <strong>the</strong> k’th year (l > k).<br />

This process is computed for each <strong>of</strong> <strong>the</strong> K seasons. Then rank <strong>the</strong> N ′ 1 + N ′ 2 +<br />

. . . + N ′ K = N ′ <strong>in</strong>dividual slope estimates and f<strong>in</strong>d <strong>the</strong>ir median. This median is<br />

<strong>the</strong> seasonal Kendall slope estimator.<br />

22

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