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THE SCIENCE AND APPLICATIONS OF ACOUSTICS - H. H. Arnold ...

THE SCIENCE AND APPLICATIONS OF ACOUSTICS - H. H. Arnold ...

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364 14. Machinery Noise Control1 kPa (4.0 in. water gauge). Table 14.2 lists the relative sound power for a varietyof fan types. In reducing all fan noise data to this common base, the concept ofspecific sound power level allows direct comparison to be made between the octaveband levels of different types of fans. A blade frequency increment (BFI) is alsolisted in Table 14.2; this represents the number of decibels that must be added tothe level of the octave band, which includes the blade frequency in order to accountfor the presence of such a tone. Also, a means is provided for estimating the noiselevel of fans under actual operating conditions by a procedure that consists of thefollowing steps:1. Select the fan type and obtain the specific power levels in octave bands fromTable 14.2. These sound power levels are expressed in decibels re 1 pW.2. Adjust the octave-band levels for the volume flow rate and the operating pressureby adding to each octave band one of the following values:orwhere10 log Q + 20 log p t dB (for metric units) (14.3a)10 log Q + 20 log p t − 45 dB (for English units) (14.3b)Q = volume flow rate, m 3 /s or cfmp t = total pressure, kPa or inches water gauge3. Account for the blade frequency component of the fan by adding the BFI forthe fan type chosen to the octave-band level of that band which includes theblade frequency. The blade frequency is found from the use of Equation (14.2).4. The sum of the above equals the total sound power level of the radiation fromthe inlet and the outlet. Subtract 3 dB from each octave band to yield the soundpower level of radiation from the inlet or the outlet.Example Problem 2Consider a radial forward-curved fan with 24 blades, having a rotor diameter of0.8 m, and operating at 750 rpm with a volume flow rate of 18 m 3 /s and with atotal pressure of 1.5 kPa.Find the total sound output power at the inlet.SolutionWe use Table 14.2 and list the calculations at each step for each octave band levelin Table 14.3. For step 2, using Equation (14.3a)10 log Q + 20 log p t = 10 log 18 + 20 log 1.5 = 16

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