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THE SCIENCE AND APPLICATIONS OF ACOUSTICS - H. H. Arnold ...

THE SCIENCE AND APPLICATIONS OF ACOUSTICS - H. H. Arnold ...

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SolutionC.5 Equations with Complex Roots 647From Figure C.5 the inverse transform can be evaluated to yield[ω(n√ ) ]x(t) = x 0 √ω n 1 − ξ2 e−ζω nt cos ω n 1 − ξ 2t + φwhereφ = θ − π/2θ = cos −1 ξand we now havex(0√ )x(t) = √1 − ξ2 e−2ω nt cos ω n 1 − ξ 2t − π/2 + cos −1 ξ

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