SPW Product Catalogue 2019

S
D
L
FACTS & FIGURES
GEOMETRIC SHAPES - PERIMETERS AND AREAS CONT.
L
Octagon
Perimeter = P
P = 8 x S
Area = A
A = 0.828 x L2
GEOMETRIC SHAPES - SURFACE AREA, LENGTH OF WELDING AND VOLUMES
B
L
H
D
R
H
SH
D
R
H
D
6
Rectangular & Square Tanks
Surface Area = SA
SA = 2 (L x B) + 2 (L x H) + 2 (B x H)
Length of Welding = LW
LW = 4L + 4B + 4H
Volume = V
V = L x B x H
Cylinder
Surface Area = SA
SA = π x D x H + 2 x π x D 2
4
Length of Welding = LW
LW = 2 x π x D + H
Volume = V
V = π x R 2 x H
or
V = 0.7854 x D 2 x H
Cone
Surface Area = SA
SA = π x D x SH + π x D 2
2 4
SH = √H 2 + R 2
Length of Welding = LW
LW = π x D = SH
Volume = V
V = π x R 2 x H
3
V = 0.2618 x D 2 x H
Sphere
Surface Area = SA
SA = π x D 2
Volume = V
V = π x D 3
6
or
V = 0.5236 x D 3
d
W
d
MD
D
D
h
H
B
L
1 m 3 contains 1000 litres.
1 litre of water has a mass of 1kg.
1 m 3 of water has a mass of 1000 kg
Annulus
Surface Area = SA
SA = π x MD x W
or
SA = π (D 2 - d 2 )
4
or
SA = 0.7854 (D2 - d2)
Hollow Cylinder
Volume = V
V = π x H (D 2 - d 2 )
or
V = 0.7854 x H (D 2 - d 2 )
Triangular Prism
Volume = V
V = H x B x L
2
Pythagoras Therom
Sin Ø =
Cos Ø =
Tan Ø =
Opposite
Hypotenuse
Adjacent
Hypotenuse
Opposite
Adjacent
Ø
Hypotenuse
Adjacent
Opposite
TECHNICAL
Copyright Produced with the permission of CIGWELD
1300 WELDER (1300 935 337)
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