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References - Bogoliubov Laboratory of Theoretical Physics - JINR

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w1 + w2 = 1<br />

� 2 pT cos<br />

2 m + p0<br />

2 ϕ − p1pT<br />

�<br />

cot ω<br />

cos ϕ + m . (17)<br />

m + p0<br />

Apparently, the terms proportional to cos ϕ disappear in the integrals (14) and the remaining<br />

terms give structure functions g1,g2 defined by Eqs. (15),(16) in [6].<br />

Now, the integration over p1 and further procedure can be done in a similar way as<br />

for unpolarized distribution. First, to simplify calculation, we assume m → 0. For w1 we<br />

get<br />

g q<br />

�<br />

1 (x) =1<br />

2<br />

The δ−function is modified as<br />

where<br />

�<br />

ΔGq(p0) 1+ p1<br />

�<br />

�<br />

p0 +<br />

�<br />

p1 dp1d<br />

(p1 − pT tan ω cos ϕ) δ − x<br />

p0<br />

M 2pT . (18)<br />

p0<br />

˜p1 = Mx<br />

2<br />

�<br />

p0 +<br />

�<br />

p1<br />

δ − x<br />

M<br />

dp1 = δ (p1 − ˜p1) dp1<br />

, (19)<br />

x/˜p0<br />

� � � �<br />

pT<br />

2<br />

1 − , ˜p0 =<br />

Mx<br />

Mx<br />

� � � �<br />

pT<br />

2<br />

1+ . (20)<br />

2 Mx<br />

Modified δ−function allows to simplify the integral<br />

g q<br />

1(x) = 1<br />

�<br />

ΔGq(˜p0)(M (2x − ξ) − 2pT tan ω cos ϕ)<br />

2<br />

d2pT ξ<br />

where<br />

Now we define<br />

Δq(x, pT )= 1<br />

2 ΔGq<br />

, (21)<br />

� � � �<br />

pT<br />

2<br />

ξ = x 1+ . (22)<br />

Mx<br />

� �<br />

Mξ<br />

2<br />

(M (2x − ξ) − 2pT tan ω cos ϕ) 1<br />

. (23)<br />

ξ<br />

According to Eq. (40) in [6] we have<br />

� �<br />

Mξ 2<br />

ΔGq =<br />

2 πM3ξ 2<br />

�<br />

3g q<br />

� 1<br />

g<br />

1(ξ)+2<br />

ξ<br />

q<br />

1(y) d<br />

dy − ξ<br />

y dξ gq<br />

�<br />

1(ξ) . (24)<br />

After inserting to Eq. (23) one gets:<br />

1<br />

Δq(x, pT ) =<br />

πM2ξ 3<br />

�<br />

3g q<br />

1 (ξ)+2<br />

� 1<br />

g<br />

ξ<br />

q<br />

1(y) d<br />

dy − ξ<br />

y dξ gq 1 (ξ)<br />

�<br />

(25)<br />

�<br />

× 2x − ξ − 2 pT<br />

�<br />

tan ω cos ϕ .<br />

M<br />

This relation allows us to calculate the distribution Δq(x, pT ) from a known input on<br />

g q<br />

1 (x). Further, it can be shown, that using the notation defined in Eqs. (9),(10), our<br />

result reads<br />

− cos ω · Δq(x, pT )=SLg q<br />

1(x, pT )+ pT ST<br />

M g⊥q<br />

1T (x, pT ), (26)<br />

162

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