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References - Bogoliubov Laboratory of Theoretical Physics - JINR

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ANOTHER NEW TRACE FORMULA FOR THE COMPUTATION OF<br />

THE FERMIONIC LINE<br />

Mustapha Mekhfi<br />

<strong>Physics</strong> Department, University Es-Senia, Oran, Algeria<br />

mekhfi@gmail.com<br />

Abstract<br />

We reexpress the fermion line as a trace over spinor indices but using the spin formalism.<br />

Our spin formulation is appropriate to the computation <strong>of</strong> dipole moments,<br />

electric or magnetic for which we have developed such formalism.Another formalism<br />

based on helicity is compared to our. We just confirm here that both formalisms<br />

are equivalent. We test the power <strong>of</strong> our trace formula by analytically computing<br />

the quark dipole magnetic moment in few lines compared to the direct computation<br />

using spinor components we made in a previous work. The trace formulation<br />

has the advantage <strong>of</strong> making the amplitudes or even the squared amplitudes easily<br />

computable either analytically or symbolically.<br />

1 The amplitude as a trace.<br />

Cross- sections and lifetimes being the squared modulus <strong>of</strong> amplitudes are traces<br />

Tr( ¯ f /p′ + m 1+γ5/s<br />

2m<br />

′ /p + m 1+γ5/s<br />

f ) (1)<br />

2 2m 2<br />

Observables such as form factors, magnetic (electric) dipole moments etc, are probability<br />

amplitudes and are usually not expressed as traces (momenta are not paired to<br />

form projectors). In this paper we propose to rewrite the amplitude as a trace<br />

ūα ′(p′ ,s ′ )fα ′ α(s ′ ,s)uα(p, s) =fα ′ α(s ′ ,s)uα(p, s)ūα ′(p′ ,s ′ )<br />

= Tr(fρ) , ραα ′ = uα(p, s)ūα ′(p′ ,s ′ (2)<br />

)<br />

The amplitude is then rewritten in term <strong>of</strong> the generalized spin density matrixρ. To<br />

find ρ we directly relate it to its form in the rest frameρ| rf ; calculate the latter then boost<br />

it again to the initial frame.<br />

u(k, s) =exp(− ω<br />

2 γ0 �γ.� k<br />

| � k| )<br />

ρ| rf = χs( � ζ)˜χ †<br />

� χs<br />

0<br />

s ′( � ζ ′ )=( 1+s� ζ.�σ<br />

2<br />

�<br />

, ū(k, s) = � χ † s , 0 � exp(− ω<br />

2 γ0 �γ.� k<br />

| � k| )γ0<br />

)( 1+s′� ζ ′ .�σ<br />

) 2<br />

After lengthy but straightforward calculations we get the expression forρ:<br />

ρ(k, s, k ′ ,s ′ /k + m<br />

)=(<br />

2m )(1+γ5 /s<br />

2<br />

ℜ =<br />

�<br />

mm ′<br />

(k0 + m)(k ′ 0 + m ′ )<br />

95<br />

(3)<br />

)ℜ( /k′ + m<br />

2m )(1+γ5 /s ′<br />

) (4)<br />

2<br />

(1 + γ0)

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