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References - Bogoliubov Laboratory of Theoretical Physics - JINR

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The Schroedinger equation is written as<br />

i� dΨ<br />

dt =[ˆ H + ˆ H ′ (t)]Ψ, (4)<br />

where ˆ H is the time-independent Hamiltonian whose eigenfunctions satisfy the equations<br />

ˆHψn = Wnψn. The exact wave function is written in the form<br />

The coefficients cn(t) must satisfy the differential equations<br />

Ψ= � cn(t)ψne −iWnt/� . (5)<br />

i� dck(t)<br />

dt = � H ′ kn (t)cn(t)e iωknt , (6)<br />

where ωkn =(Wk − Wn)/�, andH ′ kn (t) =.<br />

For the weak field transitions, one may use<br />

ˆH ′ (t) =−μhσhxBx(t)sinωt − μJSJxBx(t)sinωt − μhσhzbz(t) − μJSJzbz(t), (7)<br />

where bz(t) =(dBz/dx)vt.<br />

The matrix elements are<br />

H ′ 22 =(−μh − μJ)bz(t),<br />

H ′ 24 =[−μh sin β − (μJ/ √ 2) cos β]Bx(t)sinωt,<br />

H ′ 44 =[μh(sin 2 β − cos 2 β) − μJ sin 2 β]bz(t),<br />

H ′ 45 =[−μh sin α cos β − μJ/ √ 2(sin α sin β +cosα cos β)]Bx(t)sinωt (8)<br />

H ′ 55 =[μh(sin 2 α − cos 2 α)+μJ cos 2 α]bz(t),<br />

H ′ 56 =[−μh cos α − (μJ/ √ 2) sin α]Bx(t)sinωt,<br />

H ′ 66 =(μh + μJ)bz(t).<br />

The values <strong>of</strong> sin α, cos α, sin β, cos β, ωik are taken at the initial value <strong>of</strong> Bz(xinit). To<br />

find the final amplitude we must multiply the resulting wave function by Ψ ∗ n at the final<br />

value <strong>of</strong> the field, Bz(xfinal).<br />

Also, we need the matrix elements for the transition 1 − 3. We use the notations c1<br />

and c3.<br />

H ′ 11 =[μh(cos 2 β − sin 2 β) − μJ cos 2 β]bz(t),<br />

H ′ 13 =[μh sin β cos α − μJ/ √ 2(sin α sin β +cosα cos β)]Bx(t)sinωt (9)<br />

H ′ 33 =[μh(cos 2 α − sin 2 α)+μJ sin 2 α]bz(t),<br />

We note that at a weak magnetic field (x ≪ 1) the level distance W1 − W3 ≈− 4<br />

3 μJB,<br />

and W2 − W4 = W4 − W5 = W5 − W6 ≈− 2<br />

3 μJB. This is different from the case <strong>of</strong><br />

deuterium where all distances between the levels at F =3/2 andF =1/2 attheweak<br />

magnetic field are equal to ≈− 2<br />

3 μeB.<br />

Let we have a system <strong>of</strong> two sextupoles with the space between them. Then, realizing<br />

the transition 1 → 3 in the space between the sextupoles, after the second sextupole we<br />

get the pure state 2 with F =3/2, mF =3/2 and after ionization in a strong magnetic<br />

421

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