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References - Bogoliubov Laboratory of Theoretical Physics - JINR

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〈r 2 ch 〉≈1fm2 . Now with Eqs. (5, 3), let us actually evaluate the mean square charge<br />

radius:<br />

� �<br />

2 6<br />

rch = −<br />

F1(0)<br />

dF1(Q 2 )<br />

dQ 2<br />

�<br />

�<br />

�<br />

�<br />

� Q 2 →0<br />

= − 6 ∂<br />

F1(0) ∂Q2 � 3 d κ<br />

(2π) 3<br />

�<br />

1+ κ2 − (Q/2) 2<br />

4 〈κ0 〉 2<br />

� �<br />

ϕ κ + Q<br />

� �<br />

ϕ κ −<br />

2<br />

Q<br />

�<br />

2<br />

� �<br />

���Q→0<br />

= a 2<br />

�<br />

3<br />

2 +<br />

�<br />

1<br />

. (8)<br />

1+ 8〈κ0 〉 2 a 2<br />

3<br />

Another constraint on the model parameters comes from the proton magnetic moment,<br />

which in our additive quark model with charges eu = 2<br />

3 ep, ed = − 1<br />

3 ep appears to equal<br />

μp<br />

ep<br />

= μq<br />

eq<br />

= 1<br />

2 〈κ0 〉 F2(0) = 1<br />

2 〈κ0 � 3 d κ<br />

〉 (2π) 3 ϕ2 (κ) = 1<br />

2 〈κ0 〉 1+<br />

1<br />

3<br />

8〈κ 0 〉 2 a 2<br />

. (9)<br />

Together, constraints (8-9) may determine both free parameters <strong>of</strong> the wave function.<br />

With the experimental values μp/ep ≈ 2.79<br />

2MN , 〈r2 ch 〉≈(0.9fm)2 [1], Eqs. (8, 9) are, strictly<br />

speaking, mutually inconsistent (see Fig. 1). But within our accuracy 30 ÷ 40% they are<br />

sufficiently consistent, yielding a =0.55 ÷ 0.85 fm and 〈κ 0 〉 =50÷ 250 MeV. Similar<br />

values for a were found by other authors [3]. 3 As for 〈κ 0 〉, it is about twice smaller than<br />

typical quark mass in non-relativistic constituent models [1].<br />

Valence quark distribution function. The constructed model should also be able to<br />

describe valence quark distribution at Bjorken x150 MeV<br />

look rather unrealistic. At 〈κ0 〉�50 MeV our xqv(x) holds within the declared 30 ÷ 40%<br />

accuracy with the MRST, CTEQ pdf fits. It seems interesting that the constituent quark<br />

“mass” 〈κ0 〉 = 50 ÷ 100 MeV gets already commensurable with the pion mass scale<br />

mπ ≈ 140 MeV.<br />

�<br />

3However, if instead <strong>of</strong> (4) one took a model ϕ ∝ 1+ a2κ 2<br />

�−α 2α with α

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