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The Art of the Helicopter John Watkinson - Karatunov.net

The Art of the Helicopter John Watkinson - Karatunov.net

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Fig. 2.16 <strong>The</strong> definition <strong>of</strong> a radian. See text.<br />

Technical background 37<br />

Fig. 2.17 A sine wave is one component <strong>of</strong> a rotation. When a rotation is viewed from two places at right<br />

angles, one will see a sine wave and <strong>the</strong> o<strong>the</strong>r will see a cosine wave. <strong>The</strong> constant phase shift between sine<br />

and cosine is 90 ◦ and should not be confused with <strong>the</strong> time variant phase angle due to <strong>the</strong> rotation.<br />

would be phase shifted by 120 ◦ from that <strong>of</strong> <strong>the</strong> next blade, whereas <strong>the</strong> phase angle <strong>of</strong><br />

a blade changes continuously as it rotates. In helicopters <strong>the</strong> phase angle is taken to be<br />

<strong>the</strong> angle between <strong>the</strong> blade and a line drawn directly aft from <strong>the</strong> rotor hub.<br />

Geometrically it is possible to calculate <strong>the</strong> height or displacement <strong>of</strong> <strong>the</strong> sine wave in<br />

Figure 2.17 because it is given by <strong>the</strong> radius multiplied by <strong>the</strong> sine <strong>of</strong> <strong>the</strong> phase angle. <strong>The</strong><br />

phase angle is obtained by multiplying <strong>the</strong> angular velocity ω by <strong>the</strong> time t. Frequency<br />

f is measured in rotations per second or Hertz (Hz). Thus <strong>the</strong> phase angle at a time t<br />

is given by ωt or 2πft.<br />

A rotating object is not in static equilibrium even if <strong>the</strong> RPM is constant. With <strong>the</strong><br />

exception <strong>of</strong> those elements <strong>of</strong> <strong>the</strong> object which are on <strong>the</strong> axis <strong>of</strong> rotation, all o<strong>the</strong>r<br />

elements are in a constant state <strong>of</strong> acceleration because <strong>the</strong>ir velocity is constantly<br />

changing as <strong>the</strong>y follow a curved path. Figure 2.18(a) shows that if an arbitrary increment<br />

<strong>of</strong> time is taken, <strong>the</strong> velocity at <strong>the</strong> beginning is different from that at <strong>the</strong> end<br />

and a small resultant vector is necessary to close <strong>the</strong> triangle. As <strong>the</strong> time increment

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