Establecimiento de cuatro especies de Quercus en el sur de la ...
Establecimiento de cuatro especies de Quercus en el sur de la ...
Establecimiento de cuatro especies de Quercus en el sur de la ...
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SUPPLEMENTARY INDEX<br />
App<strong>en</strong>dix S1. Regression equations used for calcu<strong>la</strong>ting the initial seed dry mass (S DM ) using the acorn fresh mass (A FM ) for each of the mother trees. All the weights are<br />
expressed in grams. For each species, the mothers have be<strong>en</strong> numbered in the first column from 1 to 5. N and R 2 of the regressions is giv<strong>en</strong>. All the regressions are<br />
significant (P < 0.001).<br />
<strong>Quercus</strong> ilex <strong>Quercus</strong> faginea <strong>Quercus</strong> suber <strong>Quercus</strong> faginea <strong>Quercus</strong> pyr<strong>en</strong>aica<br />
1 S DM = ‐ 0.48 + 0.48 × A FM<br />
(N = 9; R 2 = 0.88)<br />
S DM = ‐ 0.12 + 0.50 × A FM<br />
(N = 10; R 2 = 0.99)<br />
S DM = ‐ 0.28 + 0.44 × A FM<br />
(N = 9; R 2 = 0.93)<br />
S DM = ‐ 0.12 + 0.50 × A FM<br />
(N = 10; R 2 = 0.99)<br />
S DM = ‐ 0.02 + 0.50 × A FM<br />
(N = 10; R 2 = 0.99)<br />
2 S DM = ‐ 0.47 + 0.52 × A FM<br />
(N = 9; R 2 = 0.97)<br />
S DM = 0.02 + 0.36 × A FM<br />
(N = 9; R 2 = 0.86)<br />
S DM = ‐ 0.58 + 0.51 × A FM<br />
(N = 8; R 2 = 0.95)<br />
S DM = 0.02 + 0.36 × A FM<br />
(N = 9; R 2 = 0.86)<br />
S DM = ‐ 0.01 + 0.49 × A FM<br />
(N = 10; R 2 = 0.97)<br />
3 S DM = ‐ 0.03 + 0.48 × A FM (N<br />
= 10; R 2 = 0.98)<br />
S DM = ‐ 0.34 + 0.57 × A FM<br />
(N = 9; R 2 = 0.94)<br />
S DM = 0.01 + 0.48 × A FM<br />
(N = 9; R 2 = 0.98)<br />
S DM = ‐ 0.34 + 0.57 × A FM<br />
(N = 9; R 2 = 0.94)<br />
S DM = ‐ 0.63 + 0.54 × A FM<br />
(N = 8; R 2 = 0.93)<br />
4 S DM = 0.37 + 0.43 × A FM<br />
(N = 9; R 2 = 0.94)<br />
S DM = ‐ 0.22 + 0.50 × A FM<br />
(N = 9; R 2 = 0.93)<br />
S DM = ‐ 0.36 + 0.52 × A FM (N =<br />
10; R 2 = 0.99)<br />
S DM = ‐ 0.22 + 0.50 × A FM<br />
(N = 9; R 2 = 0.93)<br />
S DM = ‐ 0.50 + 0.51 × A FM<br />
(N = 9; R 2 = 0.96)<br />
5 S DM = ‐ 0.04 + 0.41 × A FM<br />
(N = 8; R 2 = 0.96)<br />
S DM = ‐ 0.23 + 0.51 × A FM<br />
(N = 9; R 2 = 0.91)<br />
S DM = ‐ 0.38 + 0.50 × A FM<br />
(N = 9; R 2 = 0.96)<br />
S DM = ‐ 0.23 + 0.51 × A FM<br />
(N = 9; R 2 = 0.91)<br />
S DM = ‐ 0.22 + 0.54 × A FM<br />
(N = 9; R 2 = 0.97)