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|1.7 Mimicking Photosynthesis|<br />

H 2 + O 2<br />

(fuels)<br />

sunlight<br />

(water splitting)<br />

Cat<br />

H 2 O<br />

(exhaust)<br />

energy utilization<br />

(combustion)<br />

Figure 13: Carbon free cycle for solar energy utilization by photocatalytical hydrogen production<br />

from water.<br />

extracting (depicted in figure 13) is a main focus of current research. Ingenious is the fact that the<br />

raw material as well as the combustion product is cheap and abundant water, whereat valuable<br />

hydrogen gas will be the product as depicted for the one-electron process:<br />

2 H 2 O<br />

[photosynthesis]<br />

hν + [solar cell + electrolysis]<br />

[dye + catalyst]<br />

→ 2 H 2(g) + O 2(g) , ∆G = +1.23 eV<br />

The energy that is required for hydrogen and oxygen formation by water splitting is equivalent<br />

to the energy that is released during combustion of hydrogen (∆ f G = -272,9 kJ/mol). This is<br />

equivalent to an electric potential of -1.23 V in solution or to photons with an energy higher than<br />

hν > 1.23 eV, and accordingly to a wavelength shorter than 1008 nm (IR).<br />

However, water is no chromophore and cannot be split by absorption of light. Otherwise an<br />

electrode reaction against a high overpotential is necessary to drive the thermodynamically<br />

not accessible reaction without direct use of visible light energy. Hence, solar water splitting is<br />

accessible by electrolysis, an inefficient (5%) and expensive method when powered by photovoltaic<br />

cells. [28, 29] The process is pH dependent and occurs at standard conditions at the following<br />

potentials (vs. NHE):<br />

2 H + (aq) + 2 e− → H 2(g) , E 1/2<br />

(pH 0) = 0.00 V<br />

2 H 2 O → 4 H + (aq) + O 2(g) + 4 e − , E 1/2 (pH 0) = +1.23 V |18|

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