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FSUTMS Comprehensive Modeling Workshop - Cambridge ...

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Overview – Equilibrium Assignment Process<br />

Equilibrium Sample – 3 paths between zones A and B<br />

<strong>FSUTMS</strong>--CUBE MODELING TRAINING SERIES<br />

A<br />

A<br />

A<br />

100<br />

0<br />

0<br />

Iteration 0<br />

0<br />

100<br />

0<br />

25<br />

75<br />

0<br />

Iteration 1<br />

B<br />

► First all-or<br />

or-nothing assignment, all<br />

100 trips from A to B are assigned<br />

to the top path.<br />

► The first iteration of capacity<br />

restraint adjusts the link time on<br />

that path based upon the BPR<br />

curve and reloads the network,<br />

again using an all-or<br />

or-nothing<br />

assignment. This results in 100<br />

trips on the center path which is<br />

now the minimum path.<br />

► Program computes a combining<br />

factor using a non-linear algorithm.<br />

In this example the factor is 0.75,<br />

or .75 x 100 to center path and .25<br />

x 100 to top path.<br />

7<br />

Overview – Equilibrium Assignment Process<br />

Equilibrium Sample (Cont'd)<br />

A<br />

0<br />

0<br />

100<br />

B<br />

A<br />

19<br />

58<br />

23<br />

B<br />

Iteration 2<br />

► Second iteration, again using an<br />

all-or<br />

or-nothing assignment, results<br />

in 100 trips on the bottom path<br />

which is now the minimum path.<br />

► Program then computes a<br />

combining factor using a non-linear<br />

algorithm. In this example the<br />

factor is 0.23, or 0.23 x 100 to<br />

bottom path. This leaves 0.77 for<br />

the other paths - 0.77 x 25 to the<br />

top path and 0.77 x 75 to the<br />

bottom path. Note that 19 + 58 +<br />

23 = 100 trips.<br />

<strong>FSUTMS</strong>--CUBE MODELING TRAINING SERIES<br />

8<br />

9-4

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