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DIFFERENTIAL GEOMETRY: A First Course in Curves and Surfaces

DIFFERENTIAL GEOMETRY: A First Course in Curves and Surfaces

DIFFERENTIAL GEOMETRY: A First Course in Curves and Surfaces

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40 Chapter 2. <strong>Surfaces</strong>: Local Theoryif angles measured <strong>in</strong> the uv-plane agree with correspond<strong>in</strong>g angles <strong>in</strong> T P M for all P .Weleave itto the reader to check <strong>in</strong> Exercise 5 that this is equivalent to the conditions E = G, F =0.S<strong>in</strong>cewe have[EF]F=G[]x u · x u x u · x vx v · x u x v · x v⎡| |⎢= ⎣ x u x v| |⎤⎥⎦T ⎡| |⎢⎣ x u x v| |⎛⎡⎤⎞([]) x u · x u x u · x v 0EG − F 2 x u · x u x u · x v ⎜⎢⎥⎟= det= det ⎝⎣x v · x u x v · x v 0 ⎦⎠x v · x u x v · x v0 0 1⎛⎡⎤T ⎡ ⎤⎞⎛ ⎡ ⎤⎞| | | | | || | |= det ⎜⎢⎥ ⎢ ⎥⎝⎣x u x v n ⎦ ⎣ x u x v n ⎦⎟⎠ = ⎜ ⎢ ⎥⎟⎝det ⎣ x u x v n ⎦⎠| | | | | || | |which is the square of the volume of the parallelepiped spanned by x u , x v , <strong>and</strong> n. S<strong>in</strong>ce n is a unitvector orthogonal to the plane spanned by x u <strong>and</strong> x v , this is, <strong>in</strong> turn, the square of the area of theparallelogram spanned by x u <strong>and</strong> x v . That is,EG − F 2 = ‖x u × x v ‖ 2 ≠0.We rem<strong>in</strong>d the reader that we obta<strong>in</strong> the surface area of the parametrized surface x: U → M bycalculat<strong>in</strong>g the double <strong>in</strong>tegral∫∫ √‖x u × x v ‖dudv = EG − F 2 dudv.UU⎤⎥⎦ ,2,EXERCISES 2.11. Derive the formula given <strong>in</strong> Example 1(e) for the parametrization of the unit sphere.2. Compute I (i.e., E, F , <strong>and</strong> G) for the follow<strong>in</strong>g parametrized surfaces.*a. the sphere of radius a: x(u, v) =a(s<strong>in</strong> u cos v, s<strong>in</strong> u s<strong>in</strong> v, cos u)b. the torus: x(u, v) =((a + b cos u) cos v, (a + b cos u) s<strong>in</strong> v, b s<strong>in</strong> u) (0

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