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DIFFERENTIAL GEOMETRY: A First Course in Curves and Surfaces

DIFFERENTIAL GEOMETRY: A First Course in Curves and Surfaces

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86 Chapter 3. <strong>Surfaces</strong>: Further Topicsa. Calculate the geodesic curvature of the circle u = u 0 <strong>and</strong> compute∫κ g ds.∂M rb. Calculate χ(M r ).∫∫c. Use the Gauss-Bonnet Theorem to compute KdA. F<strong>in</strong>d the limit as r →∞. (ThisM ris the total curvature of the pseudosphere.)∫∫d. Calculate the area of M r directly, <strong>and</strong> use this to deduce the value of KdA.e. Expla<strong>in</strong> the relation between the total curvature <strong>and</strong> the image of the Gauss map of M.11. Check the details of the proof of Theorem 1.5 <strong>in</strong> the presence of corners. (See Exercise 1.3.6.)12. a. Use Corollary 1.3 to prove that M is flat if <strong>and</strong> only if the holonomy around all (“small”)closed curves that bound a region <strong>in</strong> M is zero.b. Show that even on a flat surface, holonomy can be nontrivial around certa<strong>in</strong> curves.13. Reprove the result of Exercise 2.3.13 by consider<strong>in</strong>g the holonomy around a (sufficiently small)quadrilateral formed by four of the l<strong>in</strong>es. Does the result hold if there are two families ofgeodesics <strong>in</strong> M always <strong>in</strong>tersect<strong>in</strong>g at right angles?14. Suppose α is a closed space curve with κ ≠0. Assume that the normal <strong>in</strong>dicatrix (i.e., thecurve traced out on the unit sphere by the pr<strong>in</strong>cipal normal) is a simple closed curve <strong>in</strong> theunit sphere. Prove then that it divides the unit sphere <strong>in</strong>to two regions of equal area. (H<strong>in</strong>t:Apply the Gauss-Bonnet Theorem to one of those regions.)15. Suppose M ⊂ R 3 is a closed, oriented surface with no boundary with K>0. It follows thatM is topologically a sphere (why?). Prove that M is convex; i.e., for each P ∈ M, M lies ononly one side of the tangent plane T P M. (H<strong>in</strong>t: Use the Gauss-Bonnet Theorem <strong>and</strong> Gauss’sorig<strong>in</strong>al <strong>in</strong>terpretation of curvature <strong>in</strong>dicated <strong>in</strong> the remark on p. 48 to show the Gauss mapmust be one-to-one. Then look at the end of the proof of Theorem 3.4 of Chapter 1.)M2. An Introduction to Hyperbolic GeometryHilbert proved <strong>in</strong> 1901 that there is no surface (without boundary) <strong>in</strong> R 3 with constant negativecurvature with the property that it is a closed subset of R 3 (i.e., every Cauchy sequence of po<strong>in</strong>ts<strong>in</strong> the surface converges to a po<strong>in</strong>t of the surface). The pseudosphere fails the latter condition.Nevertheless, it is possible to give a def<strong>in</strong>ition of an “abstract surface” (not sitt<strong>in</strong>g <strong>in</strong>side R 3 )together with a first fundamental form. As we know, this will be all we need to calculate Christoffelsymbols, curvature (Theorem 3.1 of Chapter 2), geodesics, <strong>and</strong> so on.Def<strong>in</strong>ition. The hyperbolic plane H is def<strong>in</strong>ed to be the half-plane {(u, v) ∈ R 2 : v > 0},equipped with the first fundamental form I given by E = G =1/v 2 , F =0.Now, us<strong>in</strong>g the formulas (‡) onp.55, we f<strong>in</strong>d thatΓ u uu = E u2E =0Γv uu = − E v2G = 1 v

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