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DIFFERENTIAL GEOMETRY: A First Course in Curves and Surfaces

DIFFERENTIAL GEOMETRY: A First Course in Curves and Surfaces

DIFFERENTIAL GEOMETRY: A First Course in Curves and Surfaces

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94 Chapter 3. <strong>Surfaces</strong>: Further Topicsb. Describe the three types of isometries geometrically. (H<strong>in</strong>t: In particular, what is therelation between horocycles <strong>and</strong> parabolic l<strong>in</strong>ear fractional transformations?)14. Suppose △ABC is a hyperbolic right triangle with “hypotenuse” c. Use Figure 2.8 to provethe follow<strong>in</strong>g:s<strong>in</strong> ∠A = s<strong>in</strong>h as<strong>in</strong>h c ,tanh bcos ∠A = , cosh c = cosh a cosh b.tanh b(The last is the hyperbolic Pythagorean Theorem.) (H<strong>in</strong>t: Start by show<strong>in</strong>g, for example, thatRψτBa cC brθAFigure 2.8cosh b = csc θ, cosh c =(1− cos ψ cos τ)/(s<strong>in</strong> ψ s<strong>in</strong> τ), <strong>and</strong> cos τ − cos ψ = s<strong>in</strong> τ cot θ. You willneed two equations trigonometrically relat<strong>in</strong>g R <strong>and</strong> r.)15. Given a po<strong>in</strong>t P on a surface M, wedef<strong>in</strong>e the geodesic circle of radius R centered at P to bethe locus of po<strong>in</strong>ts whose (geodesic) distance from P is R. Let C(R) denote its circumference.a. Show that on the unit sphere2πR − C(R)limR→0 + πR 3 = 1 3 .b. Show that the geodesic curvature κ g of a spherical geodesic circle of radius R iscot R ≈ 1 R2R(1 −3 + ...).The Po<strong>in</strong>caré disk is def<strong>in</strong>ed to be the “abstract surface” D = {(u, v) :u 2 + v 2 < 1} with the4first fundamental form given by E = G =(1 − u 2 − v 2 , F =0. This is called the hyperbolic) 2metric on D.c. Check that <strong>in</strong> D the geodesics through the orig<strong>in</strong> are Euclidean l<strong>in</strong>e segments; concludethat the ( Euclidean ) circle of radius r centered at the orig<strong>in</strong> is a hyperbolic circle of radius1+rR =ln , <strong>and</strong> so r = tanh R 1 − r2 .d. Check that the circumference of the hyperbolic circle is 2π s<strong>in</strong>h R ≈2π(R + R36 + ...), <strong>and</strong> so 2πR − C(R)limR→0 + πR 3 = − 1 3 .e. Compute (us<strong>in</strong>g a double <strong>in</strong>tegral) that the area of a disk of hyperbolic radius R is4π s<strong>in</strong>h 2 R 2≈ πR2 (1 + R212+ ...). Use the Gauss-Bonnet theorem to deduce that thegeodesic curvature κ g of the hyperbolic circle of radius R is coth R ≈ 1 R2R(1 +3 + ...).16. Here we give another model for hyperbolic geometry, called the Kle<strong>in</strong>-Beltrami model. Considerthe follow<strong>in</strong>g parametrization of the hyperbolic disk: Start with the open unit disk,

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