Flight and Operation Manual Rev 3.0 on 09-04-2013 - Trixy Aviation

5.5 Determining the center of gravityExplanation:Hereafter is an example (see weighing report in section 5.3).Weight in kg X in mm X-MomentEmpty weight 272 2320 631040Pilot 80 1190 95200Co-Pilot 73 1950 142350Luggage 5 1950 9750Fuel 20 2215 44300Summ 450 922640CG= 922640 / 450 = 2050 cm from datumThe empty mass of the gyrocopter is 272 kg (last valid).The center of gravity is located 2320 mm from the Pitot-tube’s leadingedge in X-direction.The X-Moment = 272 * 2320 = 631040Sum of all weights = 450 kgSum of all X-moments = 922290The CG of the loaded gyrocopter in X-direction is calculated:922290 / 450 = 2050 mmWarning: The center of gravity must be within the following limits:In X-direction between 1900 mm <strong>and</strong> 2200 mmThe pilot’s mass must be between 65 <strong>and</strong> 125 kg.The valid MTOF must be observed.The CG is calculated by the pilot in comm<strong>and</strong> in the following table (forhelp see example above):<strong>Flight</strong> <strong>and</strong> operation manual G 4-2 <strong>Rev</strong>ision <strong>3.0</strong> – 09.04.2013 55