Cálculo integral em R
Cálculo integral em R
Cálculo integral em R
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15.<br />
16.<br />
π2 <br />
0<br />
1<br />
3<br />
<br />
0<br />
Resolução<br />
1.<br />
2.<br />
b<br />
a<br />
1<br />
0<br />
cos √ xdx.<br />
2dx<br />
√ 4 − 9x 2 .<br />
<br />
k dx = k<br />
a<br />
b<br />
<br />
x2 xdx =<br />
2<br />
1dx = k[x] b a<br />
1<br />
0<br />
= 1<br />
2 .<br />
= k(b − a).<br />
3. Record<strong>em</strong>os que P f ′ f α = fα+1<br />
α + 1 + Cte (α = −1). Assim,<br />
6<br />
2<br />
√ x + 1 dx =<br />
6<br />
2<br />
= 2<br />
3<br />
4. Record<strong>em</strong>os que P (f ′ e f ) = e f + C te . Assim,<br />
3<br />
1<br />
e −x <br />
dx = −<br />
5. T<strong>em</strong>-se f(x) = |2 − x| =<br />
3<br />
1<br />
1<br />
3<br />
|2 − x|dx =<br />
CAPÍTULO 1. CÁLCULO INTEGRAL<br />
(x + 1) 1<br />
2 dx =<br />
<br />
(x + 1) 3<br />
6 2<br />
2<br />
<br />
(x + 1) 3<br />
2<br />
3<br />
2<br />
6<br />
2<br />
=<br />
3 (732<br />
− 3 3<br />
2).<br />
−e −x dx = − e −x 3<br />
1 = −(e−3 − e −1 ) = e −1 − e −3 .<br />
<br />
2 − x, 2 − x ≥ 0<br />
x − 2, 2 − x ≤ 0 =<br />
<br />
2 − x, 1 ≤ x ≤ 2<br />
x − 2, 2 ≤ x ≤ 3<br />
2<br />
1<br />
3<br />
(2 − x)dx + (x − 2)dx<br />
<br />
= 2x − x2<br />
2 <br />
x2 +<br />
2 1 2<br />
<br />
= (4 − 2) − 2 − 1<br />
2<br />
2<br />
<br />
+<br />
3 − 2x<br />
2<br />
<br />
9<br />
− 6<br />
2<br />
2<br />
. Assim<br />
<br />
− (2 − 4) = 1,<br />
como pod<strong>em</strong>os constatar imediatamente analisando o gráfico da função.<br />
ISA/UTL – Licões de Mat<strong>em</strong>ática – 2005 8