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The Alchemy Key.pdf - Veritas File System

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Pyramid, make it into a Cross Patté and inscribe a circle. <strong>The</strong> area of the<br />

circle is twice that of the square base of the pyramid. Using a square<br />

made from the diagonal of the base of the pyramid rather than the base of<br />

the pyramid itself, the ‘twice’ factor disappears. This is because the<br />

diagonal measures s√2. <strong>The</strong> area of such a square is 2.s 2 . Thus the<br />

esoteric solution from the Perfect Pyramid is:<br />

Area of Inscribed Patté Circle ≈ Area of a square of the Hypotenuse<br />

of the Base of the Pyramid<br />

This formula is based on an assumed value of<br />

[¼ . π.Φ 2 ] of two, which introduces an error of 2.8%.<br />

An even better approximation derives quite simply<br />

from a Jerusalem or Teutonic Cross. 1462<br />

A Chessboard solves the problem of ‘Squaring<br />

the Circle’: 1463<br />

1. Divide the Square into a Chessboard matrix.<br />

2. With a pair of Compasses centered in the middle<br />

of the Chessboard, draw a Circle so it passes<br />

through points on each side, each two squares in<br />

from each corner. This circle has an area that<br />

equals that of the square with an error of 1.8%,<br />

less than the 2.8% inherent in the Perfect Pyramid<br />

method. Schoolchildren sometimes prove the<br />

areas are equal using paper. <strong>The</strong>y cut away the<br />

corners of the square and rearrange these<br />

trimmings to fill the segments of the circle.<br />

3. Again with the Compasses draw a circle so it<br />

passes through points on each side that are one<br />

square in from each corner. This circle has the<br />

same perimeter as the square. <strong>The</strong> error is also<br />

about 1.8%.<br />

Ancient architects often wanted to Square the<br />

Circle to create a circular column of known cross<br />

section that could be set onto a square base. <strong>The</strong>ir<br />

portable calculator for ‘Squaring the Circle’ was a simple 2 x 1<br />

rectangular tablet. Draw a circle through one corner while centering on<br />

the corner diagonally opposite. <strong>The</strong> square has an area equal to 8 tablets.<br />

420

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