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Technical Information

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<strong>Technical</strong> <strong>Information</strong><br />

<strong>Technical</strong> <strong>Information</strong><br />

KM Application Data<br />

Operating Conditions<br />

The KM tooling joint is an extremely rigid and stable system that is specifically<br />

designed to supply consistent results. As with any mechanical coupling, KM has<br />

limits that, if exceeded, could result in mechanical damage to the joint and/or its<br />

components. To help you stay within these limits, Kennametal has established<br />

maximum safe tangential loads for each system size. These loads are described<br />

as a certain amount of force at the standard “F” and “L1” dimensions for each<br />

given system size.<br />

Example of Calculation:<br />

Where: P = rated tangential load<br />

K = empirical coefficient depending on<br />

KM system size and the units of measure<br />

P =<br />

KM32 K=190200<br />

KM40 K=383600<br />

KM50 K=887400<br />

KM63 K=1718000<br />

KM80 K=3085800<br />

K<br />

(0.8 L1) 2 + F 2<br />

Chart 1 F and L1 Dimensions (mm) vs. Tangential Loads (N)<br />

for KM32TS<br />

120<br />

Given: The KM integral shank boring bar, ordering code<br />

KM40TS S32G-MCLNR12<br />

Dimensions: L1 = 90mm (3.543")<br />

F = 22mm (0.866")<br />

Required: What is maximum permissible tangential load?<br />

M38 www.kennametal.com<br />

F<br />

(mm)<br />

P =<br />

100<br />

80<br />

60<br />

40<br />

20<br />

4000<br />

4700<br />

5400<br />

0<br />

0 20 40 60 80 100 120 140<br />

383600<br />

L1 (mm)<br />

Example<br />

IMPORTANT<br />

<strong>Information</strong> shown on the following charts was developed exclusively for use with KM tooling in static conditions. Do not use for any other tooling<br />

system because the results will not apply. To account for cutting force fluctuations in dynamic conditions, a reduction of 20–30% should be applied<br />

to the loads shown in charts.<br />

3400<br />

2700<br />

(0.8 x 90) 2 + 22 2<br />

2400<br />

2000<br />

1700<br />

= 5095 N<br />

(continued)

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