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Ambient Air quality Monitoring Guidlines. - Maharashtra Pollution ...

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9.4 Blank Correction - Measure the absorbance of the unexposed reagent and<br />

subtract the value from the absorbance of the sample.<br />

9.5 Calibration and Standardization<br />

9.5.1 Calibrating solutions are made up to 10 ml to facilitate the calculations:<br />

9.5.2 Obtain a range of calibration points containing from 1 µl to 10 µl of ozone<br />

equivalent per 10.0 ml of solution. Prepare by individually adding 1.0, 2.0, 4.0,<br />

6.0, 8.0 and 10.0 mL of the calibrating iodine solution (Section 9.4.2) to 10.0 ml<br />

volumetric flasks. Bring each to the calibration mark with absorbing reagent.<br />

9.5.3 Read the absorbance of each of the prepared calibration solutions as described<br />

in Section 10.3 and 10.4.<br />

9.5.4 Plot the absorbance of the obtained colors against the concentration of O3 in<br />

µl/10 ml absorbing reagent. The plot follows Beer's law. Draw the straight line<br />

through the origina giving the best fit, or fit by least squares. Do not extrapolate<br />

beyond the highest concentration.<br />

10.0 CALCULATIONS<br />

10.1 Standard conditions are taken as 101.3 kPa and 25 o C, at which the molar gas<br />

volume is 24.47 liters.<br />

10.2 Record the volume of sample collected in liters. Generally the correction of the<br />

sample volume to standard conditions is slight and may be omitted. However, for<br />

greater accuracy corrections may be calculated by means of the perfect gas<br />

laws.<br />

10.3 The total µl of O3/10 ml of reagent are read from the calibration curve.<br />

10.4 The concentration of O3 in the gas phase in µl/l or ppm is given by :<br />

Total µl ozone per 10 ml<br />

O3 ppm = -------------------------------<br />

Volume of air sample, L<br />

10.5 The concentration of O3 in terms of µg/m 3 at 101.3 kPa and 25 o C is obtained<br />

when desired from the value of µl/l (Section 11.4) by :<br />

ppm x 48.00<br />

µg O3/m3 = ------------------ x 10 3<br />

24.47<br />

= 1962 x ppm<br />

144

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