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Electromagnetic Testing Chapter 3- Electromagnetic Testing

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Calculation on the aforementioned scenario:<br />

Frequency = 100kHz maximum. In the worst case, the period of one full cycle<br />

would be 1/10,000 or 0.0001 second.With a ¼ inch diameter probe, we can<br />

move the probe or test object ¼ inch in 0.0001 second. Area of probe =<br />

π0.25 2 /4<br />

Total test time for a 100% surface inspection 3-inch diameter by 30-ft-long<br />

tube, would:<br />

Area of pipe surface= (3π x 30 x 12) in 2<br />

Total test time = 3π x 30 x 12 / (π0.25 2 /4) x 0.0001 = (3x4x30x12x4x4) x<br />

0.0001 s<br />

= 6.912s<br />

Revolution to traverse 30’ by ¼ “ probe without overlapped = 30x12/0.25=<br />

30x12x4=1440 revolution<br />

RPS= 1440/6.912 =208.3 RPS or 12498rpm.<br />

Charlie Chong/ Fion Zhang

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