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Subatomic Physics

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9.6. The Two-State Problem 261<br />

Hamiltonian is invariant under reflections through the origin, and H and the parity<br />

operator P commute,<br />

[H, P] =[H0 + Hint,P]=0. (9.61)<br />

With the choice of coordinates shown in Fig. 9.9, the parity operator gives<br />

P |L〉, = |R〉 P |R〉 = |L〉. (9.62)<br />

The simultaneous eigenfunctions of H0 and P are easy to find; they are the symmetric<br />

and antisymmetric combinations of the unperturbed states |L〉 and |R〉:<br />

� �<br />

1<br />

1<br />

|s〉 = 2 {|L〉 + |R〉}, |a〉 = 2 {|L〉−|R〉}. (9.63)<br />

These combinations indeed are eigenstates of P ,<br />

P |s〉 =+|s〉, P|a〉 = −|a〉. (9.64)<br />

Eqs. (9.61) and (9.64) together prove that H does not connect |a〉 and |s〉:<br />

or<br />

〈a|H|s〉 = 〈a|HP|s〉 = 〈a|PH|s〉 = 〈a|P † H|s〉 = −〈a|H|s〉,<br />

〈a|H|s〉 =0. (9.65)<br />

Ordinary perturbation theory can consequently be applied to the states |a〉 and |s〉.<br />

The energy shift caused by the perturbation, Hint, is given by the expectation value<br />

of Hint, or<br />

where<br />

〈s|Hint|s〉 = E ′ +∆E<br />

〈a|Hint|a〉 = E ′ − ∆E, (9.66)<br />

〈L|Hint|L〉 = 〈R|Hint|R〉 = E ′<br />

〈L|Hint|R〉 = 〈R|Hint|L〉 =∆E. (9.67)<br />

The interaction lowers the center of the energy levels by E ′ and splits the degenerate<br />

levels by an amount 2∆E, as indicated in Fig. 9.9(b). The splitting shows up in<br />

the hydrogen molecule ion and particularly clearly in the inversion spectrum of<br />

ammonia. (24)<br />

24Two-state systems and the ammonia MASER are beautifully treated in R. P. Feynman, R. B.<br />

Leighton, and M. Sands, The Feynman Lectures on <strong>Physics</strong>, Vol. III, Addison-Wesley, Reading,<br />

Mass., 1965, Chapters 8–11.

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