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Subatomic Physics

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478 Quark Models of Mesons and Baryons<br />

their quark constituents are<br />

ρ + = ud<br />

ρ 0 =<br />

ρ − = du.<br />

dd − uu<br />

√ 2<br />

(15.7)<br />

These quark combinations also apply to the pions; the difference between the rho<br />

and the pion lies in the ordinary spin. The rho is a vector meson (J π =1 − ), while<br />

the pion is a pseudoscalar meson (J π =0 − ). The other neutral mesons will be<br />

discussed in Section 15.6.<br />

If masses beyond 1 GeV/c 2 are considered, mesons of orbital angular momentum<br />

l =1� begin to appear, with J π =0 + , 1 + ,and2 + ; they correspond to qq states<br />

1 P1, 3 P0, 3 P1, and 3 P2; the isospin can be zero or one, as for the lower mass mesons.<br />

15.5 Baryons as Bound Quark States<br />

Three quarks form a baryon. Since quarks are fermions, the overall wave function<br />

of the three quarks must be antisymmetric; the wave function must change sign<br />

under any interchange of two quarks:<br />

|q1q2q3〉 = −|q2q1q3〉. (15.8)<br />

To explain why the wave function of the three quarks must be antisymmetric, the<br />

ideas expounded in Chapter 8 are generalized. There, with the introduction of<br />

isospin, proton and neutron were considered to be two states of the same particle.<br />

The total wave function, including isospin, of a two-nucleon system then must be<br />

antisymmetric under exchange of the two nucleons. Here it is assumed that the three<br />

quarks are three states of the same particle, and Eq. (15.8) is then the expression<br />

of the Pauli principle. The simplest situation arises when the three quarks have no<br />

orbital angular momentum between any pairs and have their spins parallel. The<br />

resultant baryon then has spin 3/2 and positive parity. As in the case of the mesons,<br />

it is straightforward to find the quantum numbers of the various quark combinations.<br />

Consider, for instance, the combination uuu.<br />

uuu : A =1,S =0,I3 = 3<br />

,q =2e, J =<br />

2<br />

� �<br />

3<br />

,<br />

2<br />

where S is the strangeness. These are just the quantum numbers of the ∆ ++ ,<br />

the doubly charged member of the ∆(1232). For a ∆ ++ , however, with all spin<br />

components parallel (J =3/2,Jz =3/2) and all quarks in S + states, or no orbital<br />

angular momentum, the wavefunction is symmetric under interchange of any pair<br />

of quarks.

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