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Subatomic Physics

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306 The Electromagnetic Interaction<br />

to be simultaneous, Møller and Bhabha scattering can be separated cleanly from<br />

Rutherford scattering. A second disadvantage of the approach just outlined is not<br />

so easily overcome: The energy available in the c.m. to explore the structure of the<br />

electromagnetic interaction is small because of the small electron rest mass. We<br />

have studied this problem in Section 2.7; in Eq. (2.32) we found the total energy<br />

available in the c.m.,<br />

W ≈ (2E0mec 2 ) 1/2 . (10.83)<br />

With E0 = 10 GeV, the total energy available in the c.m. becomes<br />

W ≈ 100 MeV.<br />

Even at 10-GeV incident energy there is not enough c.m. energy to even produce a<br />

muon pair. The path around this difficulty has already been shown in Section 2.8;<br />

it is the use of colliding beams. As e + e − collisions have yielded some of the most<br />

beautiful results and promise to continue to do so, we will discuss a few of the<br />

experiments and data in the following sections.<br />

One interesting concept occurs in connection with Bhabha scattering. The virtual<br />

photons in the photon-exchange and in the annihilation diagram (Fig. 10.11(c)<br />

and (d)) have very different properties. Both photons are virtual and do not satisfy<br />

the relation E = pc. Consider both reactions in the c.m. In the exchange diagram,<br />

the incoming and the outgoing electrons have the same energies but opposite<br />

momenta. Consequently, energy and momentum of the virtual photon are given by<br />

Eγ = Ee − E ′ e =0, p γ = p e − p ′ e =+2p e. (10.84)<br />

If we define a “mass” for the virtual photon through the relation E 2 =(pc) 2 +<br />

(mc 2 ) 2 , we find (11)<br />

(mc 2 ) 2 = −(2pec) 2 < 0. (10.85)<br />

The virtual photon in the exchange diagram carries only momentum—no energy.<br />

The square of its mass is negative. Such a photon is called spacelike. In the annihilation<br />

diagram, the situation is reversed,<br />

Eγ = E e − + E e + =2E, p γ = p e − + p e + =0. (10.86)<br />

The virtual photon carries only energy—no momentum. The square of its mass is<br />

given by<br />

(mc 2 ) 2 =(2E) 2 > 0; (10.87)<br />

it is positive and the photon is called timelike. In electron-positron scattering, both<br />

spacelike and timelike photons enter. The agreement of experiment with theory<br />

indicates that these concepts are correct, even if they sound strange at first.<br />

11 The “mass” defined here is related to the four-momentum transfer, q, bym 2 =(q/c) 2 . It is<br />

equal to the actual particle mass only for free particles.

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