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Subatomic Physics

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18.3. Rotational Families 551<br />

A spinless nucleus can have a permanent deformation (intrinsic quadrupole moment),<br />

and its effect can be seen in the existence of rotational levels and also in the<br />

rates of transitions leading to and from the J = 0 level. However, the quadrupole<br />

moment cannot be observed directly because the absence of a finite spin does not<br />

permit singling out a particular axis. In any measurement, an average over all directions<br />

is involved, and the permanent deformation appears only as a particularly<br />

large skin thickness.<br />

18.3 Rotational Families<br />

Deformed nuclei with spin zero in their ground state give rise to a rotational band,<br />

with spin-parity assignments 0 + , 2 + ,... Since many deformed nuclei with spins different<br />

from zero exist, the treatment of rotations must be extended to this more<br />

general case. The situation then becomes considerably more complicated, and we<br />

shall only treat the simplest case, namely a nucleus consisting of a deformed, axially<br />

symmetric, spinless core and one valence nucleon, and we shall neglect the<br />

interaction between the intrinsic and the collective (rotational) motion.<br />

Figure 18.6: (a) The deformed core gives rise to a collective<br />

angular momentum R; the valence nucleon produces<br />

an angular momentum j. (b) R and j add up<br />

to the total nuclear angular momentum J. The eigenvalue<br />

of the component of J along the symmetry axis<br />

3 is denoted by �K.<br />

We assume that the valence nucleon<br />

does not affect the core so<br />

that it behaves like the deformed<br />

spinless nucleus treated in the<br />

previous section. The core then<br />

gives rise to a rotational angular<br />

momentum R perpendicular<br />

to the symmetry axis, 3, so that<br />

R3 = 0. The valence nucleon produces<br />

an angular momentum j; R<br />

and j are shown in Fig. 18.6(a);<br />

they add up to the total nuclear<br />

angular momentum J:<br />

J = R + j. (18.19)<br />

The total angular momentum J and its component, J3, along the nuclear symmetry<br />

axis are conserved, and they satisfy the eigenvalue equations<br />

J 2 opψ = J(J +1)� 2 ψ, J3,opψ = K�ψ. (18.20)<br />

Because R3 = 0, the eigenvalue of j3,op is also given by �K.<br />

If, as assumed, the state of the valence nucleon is not affected by the collective<br />

rotation, then it is to be expected that each state of the valence nucleon can form<br />

the base (head) of a separate rotational band. In the following we shall compute the

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