12.12.2012 Views

Subatomic Physics

Subatomic Physics

Subatomic Physics

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

428 Strong Interactions<br />

gives a mass of 1232 MeV/c 2 for both processes, and it is appealing to assume<br />

that they represent the same resonance. The discovery of this resonance, called<br />

∆(1232), was already discussed in Section 5.12. The cross sections in Figs. 14.5 and<br />

14.6 show that the interaction of pions with nucleons at energies below about 500<br />

MeV is dominated by this resonance.<br />

Figure 14.7: Pion scattering<br />

and pion photoproduction at<br />

low energies are dominated<br />

by the formation of an excited<br />

nucleon, N ∗ , usually called<br />

∆(1232).<br />

Isospin and spin of ∆(1232) can be established by simple<br />

arguments. Pion (I = 1) and nucleon (I = 1<br />

2 )canform<br />

states with I = 1<br />

2<br />

and I = 3<br />

2<br />

. If ∆(1232) had I = 1<br />

2 ,only<br />

two charge states of the resonance would occur. According<br />

to the Gell-Mann–Nishijima relation, Eq. (8.30), they<br />

would have the same electric charges as the nucleons,<br />

namely 0 and 1. These two resonances, ∆ 0 (1232) and<br />

∆ + (1232), are indeed observed. In addition, however,<br />

the ∆ ++ (1232) appears in the process π + p → π + p,and<br />

∆consequentlymusthaveI = 3<br />

2 . The fourth member<br />

of the isospin multiplet, ∆− (1232), cannot be observed<br />

with proton targets; deuteron targets permit the investigation<br />

of the reaction π−n → π−n,where∆−shows up. To establish the spin of ∆(1232), we note that the<br />

maximum cross section for the scattering of unpolarized<br />

particles is given by (6)<br />

σmax =4πλ 2<br />

2J +1<br />

(2Jπ + 1)(2JN +1) =4πλ2<br />

�<br />

J + 1<br />

�<br />

.<br />

2<br />

(14.7)<br />

J, Jπ, andJNare the spins of the resonance and of the colliding particles, and<br />

λ is the c.m. reduced pion wavelength at resonance. 4πλ 2 at 155 MeV is almost<br />

100 mb, and σmax is about 200 mb, so that J + 1<br />

3<br />

2 ≈ 2orJ = 2 . To form a state with<br />

spin 3<br />

2 in pion–nucleon scattering, the incoming pions must carry one unit of orbital<br />

angular momentum. Pion–nucleon scattering at low energies occurs predominantly<br />

in p waves.<br />

• Thefactthatpion–nucleonscattering at low energies occurs predominantly<br />

in the state J = 3 3<br />

2 ,I = 2 (the so-called 3–3 resonance) can be verified by a spin–<br />

isospin phase-shift analysis. We shall not present the complete analysis here, but<br />

we shall outline its isospin part because it provides an example for the use of isospin<br />

invariance. We first note that experimental states are prepared with well-defined<br />

charges. Theoretically, however, it is more appropriate to use well-defined values of<br />

the total isospin. It is therefore necessary to express the experimentally prepared<br />

6 The maximum cross section for the scattering of spinless particles with zero orbital angular<br />

momentum is given by 4πλ 2 . A particle with spin J is (2J + 1)-fold-degenerate. By assuming that<br />

the above cross section holds for each substate, Eq. (14.7) follows.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!