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Subatomic Physics

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530 The Shell Model<br />

Here L = 1<br />

2 (x1 − x2) × (p1 − p2) is the relative orbital angular momentum of the<br />

two nucleons and S = s1 + s2 = 1<br />

2 (σ1 + σ2) is the sum of the spins.<br />

Such a term in the nucleon–nucleon force will produce<br />

aterm<br />

Vls = Clsl · s<br />

Figure 17.10: Nucleon with<br />

orbital angular momentum l<br />

and spin s moving in the nuclear<br />

potential.<br />

in the nuclear potential, where l is the orbital angular<br />

momentum of the nucleon that moves in the nuclear<br />

potential and s is its spin. To see the connection, we<br />

consider an orbit as shown in Fig. 17.10. In the interior<br />

of the nucleus, where the nuclear density is constant,<br />

there are an equal number of nucleons on either side of<br />

the orbit within reach of the nuclear force. The spin–<br />

orbit interaction consequently averages out.<br />

Near the surface, however, nucleons are only on the interior side of the orbit, the<br />

relative orbital angular momentum L in Eq. (17.12) always points in the same<br />

direction, and the two-body spin–orbit interaction gives rise to a term of the form<br />

of Eq. (17.7). To make this argument more precise, the spin–orbit interaction energy<br />

[Eq. (17.12)] between two nucleons, 1 and 2, is written as<br />

V (1, 2) = 1<br />

2VLS(r12)(x1 − x2) × (p1 − p2) · (s1 + s2). (17.13)<br />

If particle 1 is the nucleon under consideration, an estimate of the nuclear spin–orbit<br />

potential can be obtained by averaging V (1, 2) over nucleon 2,<br />

�<br />

Vls(1) = Av d 3 x2ρ(x2)V (1, 2), (17.14)<br />

where Av indicates that we must average over the spin and the momentum of<br />

nucleon 2, and where ρ(x2) is the probability density of nucleon 2. After inserting<br />

V (1, 2) from Eq. (17.13), Vls(1) becomes<br />

�<br />

Vls(1) = 1<br />

2<br />

d 3 x2ρ(x2)VLS(r12)(x1 − x2) × p 1 · s1; (17.15)<br />

the average of all other terms is zero. The nuclear density at position x2 can be<br />

expanded in a Taylor series about x1 because of the short range of the spin–orbit<br />

force:<br />

ρ(x2) =ρ(x1)+(x2 − x1) · ∇ρ(x1)+··· . (17.16)<br />

After inserting the expansion into Vls(1), the integral containing the factor ρ(x1)<br />

vanishes. The remaining integral can be computed; under the assumption that the<br />

range of the nucleon spin–orbit interaction is small compared to the nuclear surface<br />

thickness, which is the only region wherein ∇ρ is appreciable, it gives<br />

Vls(1) = C 1 ∂ρ(r1)<br />

l1 · s1, (17.17)<br />

r1 ∂r1

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