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9.8. The Fall of CP Invariance 269<br />

2. The state |K0 2<br />

transitions from |K0 2 〉 to |K0 1<br />

〉 is an eigenstate of the total Hamiltonian. In vacuum, no<br />

〉 can occur. For the two wells, the absence of<br />

such transitions is expressed by Eq. (9.65). The corresponding relation for<br />

kaons follows from Eqs. (9.80) and (9.81) as<br />

〈K 0 1 |H|K0 2 〉 =0. (9.88)<br />

3. As stated by Eq. (9.84), K 0 2 cannot decay into two pions if CP is conserved.<br />

In 1964, a Princeton group performed an experiment to set a lower limit on<br />

the two-pion decay of K 0 2 .(32) Another experiment was simultaneously done by an<br />

Illinois group. (33) Both gave the astounding result that decays into two pions do<br />

occur; the branching ratio was found to be approximately<br />

Int(K 0 L → π+ π − )<br />

Int(K 0 L → all charged modes) ≈ 2 × 10−3 . (9.89)<br />

We have switched notation here and denote the long-lived neutral kaon with K0 L<br />

and the short-lived one with K0 S . The reason for the switch is Eq. (9.82), which<br />

defines K0 1 and K0 2 to be eigenstates of CP. Equation (9.89) indicates, however,<br />

that the long-lived kaon is not an eigenstate of CP. It is customary to retain the<br />

for the eigenstates of CP and to denote the real particles with<br />

notation K0 1 and K0 2<br />

K0 S and K0 L .<br />

The news of violation of CP traveled through the world ofphysicswithnearly<br />

the speed of light, just as, seven years earlier, had the news of parity breakdown.<br />

It was greeted with even more scepticism. To describe the reason for the disbelief,<br />

we digress to describe the celebrated CPT theorem. The CPT theorem is easy to<br />

understand but difficult to prove. In a somewhat sloppy way, it can be stated as<br />

follows: the product of the three operations T , C, andPcommutes with practically<br />

every conceivable Hamiltonian, or<br />

[CPT,H]=0. (9.90)<br />

In other words, our world and a time-reversed parity-reflected antiworld must behave<br />

identically. The order of the three operators T , C, andP is irrelevant. (34) The<br />

operation CPT is thus very different from the individual operations T , C, andP .<br />

It is easy to construct a Lorentz-invariant Hamiltonian that violates, for instance,<br />

32 J. H. Christenson, J. W. Cronin, V. L. Fitch, and R. Turlay, Phys. Rev. Lett. 13, 138 (1964).<br />

V. L. Fitch, Rev. Mod. Phys. 53, 367 (1981); Science 212, 939 (1981); J. W. Cronin, Rev. Mod.<br />

Phys. 53, 373 (1981); Science 212, 1221 (1981).<br />

33 A. Abashian, R. J. Abrams, D. W. Carpenter, G. P. Fisher, B. M. K. Nefkens, and J. H.<br />

Smith, Phys. Rev. Lett. 13, 243 (1964).<br />

34 Since the order of the operations T , C, andP does not matter, there exist 3! possibilities of<br />

naming the theorem. Lüders and Zumino checked that their choice,TCP, agreed with the name of<br />

a well-known gasoline additive. Despite this, we use the more standard order, namely CPT. [G.<br />

Lüders, Physikalische Blätter 22, 421 (1966).]

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