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Subatomic Physics

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12.1. Introduction 385<br />

D0 ≡ 1 ∂ iqA0<br />

+<br />

c ∂t �c ,<br />

D ≡ ∇ − iqA<br />

�c .<br />

(12.5)<br />

If these derivatives replace the normal ones, (1/c)∂/∂t and ∇, it follows with<br />

Eqs. (7.1) and (12.2) that<br />

D ′ 0ψ ′ q = D ′ 0UQψq = UQD0ψq,<br />

D ′ ψ ′ q = D ′ UQψq = UQDψq, (12.6)<br />

where D ′ 0 and D ′ have A ′ 0 and A ′ as dependent variables. It is important to note<br />

that if UQ stands to the left of D0 and D, it is a simple phase factor, since the<br />

derivatives only act on quantities to their right. With the introduction of the gauge<br />

covariant derivatives, D0 and D transform under local gauge transformations just<br />

like 1<br />

c<br />

∂<br />

∂t<br />

and ∇ do under a global gauge transformation (ɛ = constant). The vec-<br />

tor nature of the compensating field which appears in the covariant derivative is<br />

determined by the vector property of the momentum p for the free Hamiltonian<br />

and the time dependence of Eq. (7.1). When the covariant derivative is introduced<br />

in the Schrödinger equation, including the compensating field, the resulting particle<br />

Hamiltonian has the form Eq. (12.1). Thus, the requirement of local gauge<br />

invariance generates the qA0 and j · A interaction of a charged particle with the<br />

electromagnetic field. We note, in addition, that space and time transformations<br />

are tied together.<br />

So far, we have neglected the equation of motion for the vector field (A0, A). In<br />

the case of the electromagnetic field, it is given by Maxwell’s equations (i = x, y, z)<br />

1<br />

c2 1<br />

c2 if we use the Lorentz condition<br />

∂2A0 ∂t2 − ∇2A0 = ρ = ψ ∗ qψ,<br />

∂2Ai ∂t2 − ∇2Ai = ji<br />

c<br />

= ψ∗ qvi<br />

c ψ,<br />

(12.7)<br />

1 ∂A0<br />

+ ∇·A =0. (12.8)<br />

c ∂t<br />

The equations (12.7) are invariant under the gauge transformations, Eq. (12.4), if<br />

we impose the condition<br />

1<br />

c2 • In four-vector notation Eq. (12.7) becomes<br />

�<br />

�Aµ ≡ gα ν∇α∇νAµ = jµ<br />

c .<br />

�<br />

∂ 2 ɛ(x,t)<br />

∂t 2 − ∇2 ɛ(x,t)=0. (12.9)

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