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General Design Principles for DuPont Engineering Polymers - Module

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4—Structural <strong>Design</strong><br />

Short Term Loads<br />

If a plastic part is subjected to a load <strong>for</strong> only a short<br />

time (10–20 minutes) and the part is not stressed<br />

beyond its elastic limit, then classical design <strong>for</strong>mulas<br />

found in engineering texts as reprinted here can be<br />

used with sufficient accuracy. These <strong>for</strong>mulas are<br />

based on Hooke’s Law which states that in the elastic<br />

region the part will recover to its original shape after<br />

stressing, and that stress is proportional to strain.<br />

Tensile Stress—Short Term<br />

Hooke’s law is expressed as:<br />

s = E ε<br />

where:<br />

s = tensile stress (Kg/cm 2 ) (psi)<br />

E = modulus of elasticity (Kg/cm 2 ) (psi)<br />

ε = elongation or strain (mm/mm) (in/in)<br />

The tensile stress is defined as:<br />

s = F<br />

A<br />

where:<br />

F = total <strong>for</strong>ce (Kg) (lb)<br />

A = total area (cm 2 ) (in 2 )<br />

Bending Stress<br />

In bending, the maximum stress is calculated from:<br />

sb =<br />

My<br />

=<br />

M<br />

I Z<br />

where:<br />

s = bending stress (Kg/cm2 ) (psi)<br />

M = bending moment (Kg/cm) (lb·in)<br />

I = moment of inertia (cm4 ) (in4 )<br />

y = distance from neutral axis to extreme outer<br />

fiber (cm) (in)<br />

Z = I = section modulus (cm3 ) (in3 )<br />

y<br />

The I and y values <strong>for</strong> some typical cross-sections are<br />

shown in Table 4.01.<br />

Beams<br />

Various beam loading conditions can be found in the<br />

Roark’s <strong>for</strong>mulas <strong>for</strong> stress and strain.<br />

Beams in Torsion<br />

When a plastic part is subjected to a twisting moment,<br />

it is considered to have failed when the shear strength<br />

of the part is exceeded.<br />

15<br />

The basic <strong>for</strong>mula <strong>for</strong> torsional stress is: Ss = Tr<br />

K<br />

where:<br />

Ss = Shear stress (psi)<br />

T = Twisting Moment (in·lb)<br />

r = Radius (in)<br />

K = Torsional Constant (in4 )<br />

Formulas <strong>for</strong> sections in torsion are given in Table<br />

4.02.<br />

To determine θ, angle of twist of the part whose<br />

length is , the equation shown below is used:<br />

θ = T<br />

KG<br />

where:<br />

θ = angle of twist (radians)<br />

K = Torsional Constant (in4 )<br />

= length of member (in)<br />

G = modulus in shear (psi)<br />

To approximate G, the shear modulus, use the<br />

equation,<br />

G= E<br />

2 (1+η)<br />

where:<br />

η = Poisson’s Ratio<br />

E = Modulus (psi) (mPa)<br />

Formulas <strong>for</strong> torsional de<strong>for</strong>mation and stress <strong>for</strong><br />

commonly used sections are shown in Table 4.02.<br />

Tubing and Pressure Vessels<br />

Internal pressure in a tube, pipe or pressure vessel<br />

creates three (3) types of stresses in the part: Hoop,<br />

meridional and radial. See Table 4.03.<br />

Buckling of Columns, Rings and<br />

Arches<br />

The stress level of a short column in compression is<br />

calculated from the equation,<br />

Sc = F<br />

A<br />

The mode of failure in short columns is compressive<br />

failure by crushing. As the length of the column<br />

increases, however, this simple equation becomes<br />

invalid as the column approaches a buckling mode of<br />

failure. To determine if buckling will be a factor,<br />

consider a thin column of length , having frictionless<br />

rounded ends and loaded by <strong>for</strong>ce F. As F increases,<br />

the column will shorten in accordance with Hooke’s<br />

Law. F can be increased until a critical value of P CR is<br />

reached. Any load above P CR will cause the column to<br />

buckle.

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