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Linear Algebra, Theory And Applications, 2012a

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158 SPECTRAL THEORY<br />

As an example, consider the following.<br />

Example 7.1.3 Find the eigenvalues and eigenvectors for the matrix<br />

⎛<br />

5 −10<br />

⎞<br />

−5<br />

A = ⎝ 2 14 2 ⎠ .<br />

−4 −8 6<br />

You first need to identify the eigenvalues. Recall this requires the solution of the equation<br />

⎛ ⎛<br />

det ⎝λ ⎝ 1 0 0<br />

⎞ ⎛<br />

⎞⎞<br />

5 −10 −5<br />

0 1 0 ⎠ − ⎝ 2 14 2 ⎠⎠ =0<br />

0 0 1 −4 −8 6<br />

When you expand this determinant, you find the equation is<br />

(λ − 5) ( λ 2 − 20λ + 100 ) =0<br />

and so the eigenvalues are<br />

5, 10, 10.<br />

I have listed 10 twice because it is a zero of multiplicity two due to<br />

λ 2 − 20λ + 100 = (λ − 10) 2 .<br />

Having found the eigenvalues, it only remains to find the eigenvectors. First find the<br />

eigenvectors for λ =5. As explained above, this requires you to solve the equation,<br />

⎛ ⎛<br />

⎝5 ⎝ 1 0 0 ⎞ ⎛<br />

⎞⎞<br />

⎛<br />

5 −10 −5<br />

0 1 0 ⎠ − ⎝ 2 14 2 ⎠⎠<br />

⎝ x ⎞ ⎛<br />

y ⎠ = ⎝ 0 ⎞<br />

0 ⎠ .<br />

0 0 1 −4 −8 6 z 0<br />

That is you need to find the solution to<br />

⎛<br />

⎝ −2 −9 −2<br />

0 10 5<br />

4 8 −1<br />

⎞ ⎛<br />

⎠ ⎝ x ⎞ ⎛<br />

y ⎠ = ⎝ 0 ⎞<br />

0 ⎠<br />

z 0<br />

By now this is an old problem. You set up the augmented matrix and row reduce to get the<br />

solution. Thus the matrix you must row reduce is<br />

⎛<br />

⎞<br />

−2 −9 −2 0 ⎠ . (7.3)<br />

⎝ 0 10 5 0<br />

4 8 −1 0<br />

The reduced row echelon form is<br />

⎛<br />

⎞<br />

1 0 − 5 4<br />

0<br />

⎝<br />

1<br />

0 1<br />

2<br />

0 ⎠<br />

0 0 0 0<br />

and so the solution is any vector of the form<br />

⎛<br />

5<br />

4<br />

⎝<br />

z<br />

⎞ ⎛<br />

−1<br />

2 z ⎠ = z ⎝<br />

z<br />

5<br />

4<br />

−1<br />

2<br />

1<br />

⎞<br />

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