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Linear Algebra, Theory And Applications, 2012a

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164 SPECTRAL THEORY<br />

There is nothing new about finding the eigenvectors for λ = 1 so consider the eigenvalue<br />

λ =2+i. You need to solve<br />

⎛ ⎛<br />

⎝(2 + i) ⎝ 1 0 0<br />

⎞ ⎛<br />

0 1 0 ⎠ − ⎝ 1 0 0<br />

⎞⎞<br />

⎛<br />

0 2 −1 ⎠⎠<br />

⎝ x ⎞ ⎛<br />

y ⎠ = ⎝ 0 ⎞<br />

0 ⎠<br />

0 0 1 0 1 2 z 0<br />

In other words, you must consider the augmented matrix<br />

⎛<br />

⎝ 1+i 0 0 i 0 1 0<br />

0<br />

⎞<br />

⎠<br />

0 −1 i 0<br />

for the solution. Divide the top row by (1 + i) and then take −i times the second row and<br />

add to the bottom. This yields ⎛<br />

⎝ 1 0 0 i 0 1 0<br />

0<br />

⎞<br />

⎠<br />

0 0 0 0<br />

Now multiply the second row by −i to obtain<br />

⎛<br />

⎝ 1 0 0 0<br />

0 1 −i 0<br />

0 0 0 0<br />

⎞<br />

⎠<br />

Therefore, the eigenvectors are of the form<br />

⎛<br />

⎞<br />

z<br />

⎝ 0 i<br />

1<br />

⎠ .<br />

You should find the eigenvectors for λ =2− i. These are<br />

⎛<br />

z ⎝<br />

0 ⎞<br />

−i ⎠ .<br />

1<br />

As usual, if you want to get it right you had better check it.<br />

⎛<br />

⎝ 1 0 0<br />

⎞ ⎛<br />

0 2 −1 ⎠ ⎝<br />

0 ⎞ ⎛ ⎞ ⎛<br />

0<br />

−i ⎠ = ⎝ −1 − 2i ⎠ =(2− i) ⎝<br />

0 1 2 1<br />

2 − i<br />

so it worked.<br />

0 −i<br />

1<br />

⎞<br />

⎠<br />

7.2 Some <strong>Applications</strong> Of Eigenvalues <strong>And</strong> Eigenvectors<br />

Recall that n × n matrices can be considered as linear transformations. If F is a 3 × 3real<br />

matrix having positive determinant, it can be shown that F = RU where R is a rotation<br />

matrix and U is a symmetric real matrix having positive eigenvalues. An application of<br />

this wonderful result, known to mathematicians as the right polar decomposition, is to<br />

continuum mechanics where a chunk of material is identified with a set of points in three<br />

dimensional space.

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