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Linear Algebra, Theory And Applications, 2012a

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376 NUMERICAL METHODS FOR FINDING EIGENVALUES<br />

15.1.2 The Explicit Description Of The Method<br />

Here is how you use this method to find the eigenvalue and eigenvector closest<br />

to α.<br />

1. Find (A − αI) −1 .<br />

2. Pick u 1 . If you are not phenomenally unlucky, the iterations will converge.<br />

3. If u k has been obtained,<br />

u k+1 = (A − αI)−1 u k<br />

s k+1<br />

where s k+1 is the entry of (A − αI) −1 u k which has largest absolute value.<br />

4. When the scaling factors, s k are not changing much and the u k are not changing much,<br />

find the approximation to the eigenvalue by solving<br />

s k+1 = 1<br />

λ − α<br />

for λ. The eigenvector is approximated by u k+1 .<br />

5. Check your work by multiplying by the original matrix to see how well what you have<br />

found works.<br />

Thus this amounts to the power method for the matrix (A − αI) −1 .<br />

⎛<br />

5 −14 11<br />

⎞<br />

Example 15.1.4 Find the eigenvalue of A = ⎝ −4 4 −4 ⎠ which is closest to −7.<br />

3 6 −3<br />

Also find an eigenvector which goes with this eigenvalue.<br />

In this case the eigenvalues are −6, 0, and 12 so the correct answer is −6 for the eigenvalue.<br />

Then from the above procedure, I will start with an initial vector,<br />

⎛ ⎞<br />

1<br />

u 1 ≡ ⎝ 1 ⎠ .<br />

1<br />

Then I must solve the following equation.<br />

⎛⎛<br />

5 −14 11<br />

⎞ ⎛<br />

⎝⎝<br />

−4 4 −4 ⎠ +7⎝<br />

3 6 −3<br />

1 0 0<br />

0 1 0<br />

0 0 1<br />

Simplifying the matrix on the left, I must solve<br />

⎛<br />

⎞ ⎛<br />

12 −14 11<br />

⎝ −4 11 −4 ⎠ ⎝ x y<br />

3 6 4 z<br />

⎞⎞<br />

⎛<br />

⎠⎠<br />

⎝<br />

⎞ ⎛<br />

⎠ =<br />

x<br />

y<br />

z<br />

⎝ 1 1<br />

1<br />

⎞ ⎛<br />

⎠ = ⎝<br />

and then divide by the entry which has largest absolute value to obtain<br />

⎛<br />

u 2 = ⎝ 1.0 ⎞<br />

. 184 ⎠<br />

−. 76<br />

⎞<br />

⎠<br />

1<br />

1<br />

1<br />

⎞<br />

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