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Linear Algebra, Theory And Applications, 2012a

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488 ANSWERS TO SELECTED EXERCISES<br />

10 (Ax, y) = ∑ i (Ax) i y i = ∑ ∑<br />

i k A ikx k y i<br />

(<br />

x,A T y ) = ∑ k x ∑ ( )<br />

k i A<br />

T<br />

ki y i = ∑ ∑<br />

k i x kA ik y i ,<br />

the same as above. Hence the two are equal.<br />

( )<br />

11 (AB) T x, y ≡<br />

(x, (AB) y) =<br />

(<br />

A T x,By ) = ( B T A T x, y ) (<br />

. Since this holds for every<br />

x, y, you have for all y, (AB) T x − B T A T x, y<br />

)<br />

.<br />

Let y =(AB) T x − B T A T x. Then since x is arbitrary,<br />

the result follows.<br />

13 Give an example of matrices, A, B, C such that B ≠<br />

C, A ≠0, and yet AB = AC.<br />

( )( ) ( )<br />

1 1 1 −1 0 0<br />

=<br />

1 1 −1 1 0 0<br />

( )( ) ( )<br />

1 1 −1 1 0 0<br />

=<br />

1 1 1 −1 0 0<br />

15 It appears that there are 8 ways to do this.<br />

17 ABB −1 A −1 = AIA −1 = I<br />

B −1 A −1 AB = B −1 IB = I<br />

Then by the definition of the inverse and its uniqueness,<br />

it follows that (AB) −1 exists and (AB) −1 =<br />

B −1 A −1 .<br />

19 Multiply both sides on the left by A −1 .<br />

( )( ) ( )<br />

1 1 1 −1 0 0<br />

21<br />

=<br />

1 1 −1 1 0 0<br />

23 Almost anything works.<br />

( )( ) ( )<br />

1 2 1 2 5 2<br />

=<br />

3 4 2 0 11 6<br />

( )( ) ( )<br />

1 2 1 2 7 10<br />

=<br />

2 0 3 4 2 4<br />

( )<br />

−z −w<br />

25<br />

,z,w arbitrary.<br />

z w<br />

27<br />

⎛<br />

⎝ 1 2 2 1 3<br />

4<br />

⎞<br />

⎠<br />

1 0 2<br />

−1<br />

29 Row echelon form:<br />

⎛<br />

⎝ 1 0 ⎞<br />

5<br />

3<br />

2<br />

0 1 ⎠<br />

3<br />

.Ahas no in-<br />

0 0 0<br />

verse.<br />

⎛<br />

= ⎝<br />

−2 4 −5<br />

0 1 −2<br />

1 −2 3<br />

⎞<br />

⎠<br />

G.6 Exercises<br />

2.7<br />

1 Show the map T : R n → R m defined by T (x) =Ax<br />

where A is an m×n matrix and x is an m×1 column<br />

vector is a linear transformation.<br />

This follows from matrix multiplication rules.<br />

3 Find the matrix for the linear transformation which<br />

rotates every vector in R 2 through an angle of π/4.<br />

( ) (<br />

cos (π/4) − sin (π/4)<br />

1<br />

√ )<br />

= 2 2 −<br />

1<br />

√ 2√<br />

√ 2<br />

sin (π/4) cos (π/4)<br />

1<br />

2 2<br />

1<br />

2 2<br />

5 Find the matrix for the linear transformation which<br />

rotates every vector in R 2 throughanangleof2π/3.<br />

( ) ( √ )<br />

2 cos (π/3) −2sin(π/3)<br />

= √ 1 − 3<br />

2sin(π/3) 2 cos (π/3) 3 1<br />

7 Find the matrix for the linear transformation which<br />

rotates every vector in R 2 through an angle of 2π/3<br />

and then reflects across the x axis.<br />

( )( )<br />

1 0 cos (2π/3) − sin (2π/3)<br />

0 −1 sin (2π/3) cos (2π/3)<br />

( )<br />

−<br />

1<br />

= 2<br />

− 2√ 1 3<br />

− 2√ 1 3<br />

1<br />

2<br />

9 Find the matrix for the linear transformation which<br />

rotates every vector in R 2 through an angle of π/4<br />

and then reflects across the x axis.<br />

( )( )<br />

1 0 cos (π/4) − sin (π/4)<br />

0 −1 sin (π/4) cos (π/4)<br />

( 1<br />

√ )<br />

= 2 2 −<br />

1<br />

2√<br />

√ 2<br />

− 2√ 1 2 −<br />

1 2<br />

2<br />

11 Find the matrix for the linear transformation which<br />

reflects every vector in R 2 across the x axis and then<br />

rotates every vector through an angle of π/4.<br />

( )( )<br />

cos (π/4) − sin (π/4) 1 0<br />

sin (π/4) cos (π/4) 0 −1<br />

( 1<br />

√ )<br />

= 2 2<br />

1<br />

√ 2√<br />

√ 2<br />

1<br />

2 2 −<br />

1<br />

2 2<br />

13 Find the matrix for the linear transformation which<br />

reflects every vector in R 2 across the x axis and then<br />

rotates every vector through an angle of π/6.<br />

( )( )<br />

cos (π/6) − sin (π/6) 1 0<br />

sin (π/6) cos (π/6) 0 −1<br />

√<br />

3<br />

1<br />

=<br />

( 1<br />

2<br />

2<br />

1<br />

2<br />

− 1 2<br />

√<br />

3<br />

)

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