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Linear Algebra, Theory And Applications, 2012a

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G.23. EXERCISES 497<br />

⎧⎛<br />

⎞⎫<br />

⎨ 0.209 84 ⎬<br />

⎝ 0.453 06 ⎠ ↔ 0.189 11,<br />

⎩<br />

⎭<br />

−0.866 43<br />

⎧⎛<br />

⎞⎫<br />

⎨ 0.935 48 ⎬<br />

⎝ −0.350 73 ⎠ ↔−0.703 70<br />

⎩<br />

4. 316 8 × 10 −2 ⎭<br />

⎛<br />

0 2<br />

⎞<br />

1.0<br />

5 ⎝ 2 0 3 ⎠, eigenvectors:<br />

1 3 2<br />

⎧⎛<br />

⎨<br />

⎝ 0.379 2<br />

⎞⎫<br />

⎬<br />

0.584 81 ⎠ ↔ 4. 975 4,<br />

⎩<br />

⎭<br />

0.717 08<br />

⎧⎛<br />

⎞⎫<br />

⎨ 0.814 41 ⎬<br />

⎝ 0.156 94 ⎠ ↔−0.300 56,<br />

⎩<br />

⎭<br />

−0.558 66<br />

⎧⎛<br />

⎞⎫<br />

⎨ 0.439 25 ⎬<br />

⎝ −0.795 85 ⎠ ↔−2. 674 9<br />

⎩<br />

⎭<br />

0.416 76<br />

6 |7. 333 3 − λ q |≤0.471 41<br />

7 |7 − λ q | =2. 449 5<br />

8 |λ q − 8| ≤3. 266 0<br />

9 −10 ≤ λ ≤ 12<br />

10 x 3 +7x 2 +3x +7.0 = 0, Solution is:<br />

⎧<br />

⎫<br />

⎨ [x = −0.145 83 + 1. 011i] , ⎬<br />

[x = −0.145 83 − 1. 011i] ,<br />

⎩<br />

⎭<br />

[x = −6. 708 3]<br />

11 −1. 475 5 + 1. 182 7i,<br />

−1. 475 5 − 1. 182 7i, −0.024 44 + 0.528 23i,<br />

−0.024 44 − 0.528 23i<br />

12 Let Q T AQ = H where H is upper Hessenberg.<br />

Then take the transpose of both sides. This will<br />

show that H = H T and so H iszeroonthetopas<br />

well.

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