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Linear Algebra, Theory And Applications, 2012a

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282 MARKOV CHAINS AND MIGRATION PROCESSES<br />

Proof: Let A be the above matrix and suppose Ax =λx. Then letting A ′ denote<br />

⎛<br />

⎞<br />

0 p 0 ··· 0<br />

q 0 p ··· 0<br />

. 0 q 0 ..<br />

. ,<br />

⎜<br />

.<br />

⎝ . 0 .. . .. p ⎟<br />

⎠<br />

0<br />

. 0 q 0<br />

it follows<br />

and so from the above theorem,<br />

A ′ x =(λ − a) x<br />

|λ − a| < 1. <br />

Example 11.3.6 In the gambler’s ruin problem a gambler plays a game with someone, say<br />

a casino, until he either wins all the other’s money or loses all of his own. A simple version<br />

of this is as follows. Let X k denote the amount of money the gambler has. Each time the<br />

game is played he wins with probability p ∈ (0, 1) or loses with probability (1 − p) ≡ q. In<br />

case he wins, his money increases to X k +1 and if he loses, his money decreases to X k − 1.<br />

The transition probability matrix P, describing this situation is as follows.<br />

⎛<br />

⎞<br />

1 0 0 0 ··· 0 0<br />

q 0 p 0 ··· 0 0<br />

0 q 0 p ··· 0 .<br />

P =<br />

. 0 0 q 0 ..<br />

. 0<br />

.<br />

.<br />

. 0 .. . ..<br />

p 0<br />

⎜<br />

⎝<br />

⎟<br />

0 0 . 0 q 0 p ⎠<br />

0 0 0 0 0 0 1<br />

(11.2)<br />

Here the matrix is b +1× b + 1 because the possible values of X k are all integers from 0 up<br />

to b. The 1 in the upper left corner corresponds to the gambler’s ruin. It involves X k =0<br />

so he has no money left. Once this state has been reached, it is not possible to ever leave<br />

it. This is indicated by the row of zeros to the right of this entry the k th of which gives the<br />

probability of going from state 1 corresponding to no money to state k 1 .<br />

In this case 1 is a repeated root of the characteristic equation of multiplicity 2 and all<br />

the other eigenvalues have absolute value less than 1. To see that this is the case, note that<br />

the characteristic polynomial is of the form<br />

⎛<br />

(1 − λ) 2 det<br />

⎜<br />

⎝<br />

⎞<br />

−λ p 0 ··· 0<br />

q −λ p ··· 0<br />

0 q −λ . .<br />

. . .<br />

.<br />

. 0 .. . .. p ⎟<br />

⎠<br />

.<br />

0 . 0 q −λ<br />

1 No one will give the gambler money. This is why the only reasonable number for entries in this row to<br />

the right of 1 is 0.

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