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Linear Algebra, Theory And Applications, 2012a

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F.3. TRANSCENDENTAL NUMBERS 453<br />

It follows that for ju,vbecause p is<br />

a prime number. It follows<br />

n∑<br />

f (j) (0) = v p(m−1) u p + m (p) p<br />

j=0<br />

where m (p) is some integer.<br />

Now consider the other sum in (6.6),<br />

c<br />

m∑<br />

i=1 j=0<br />

n∑<br />

f (j) (β i )<br />

Using the formula in (6.7) it follows that for j

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