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Linear Algebra, Theory And Applications, 2012a

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86 DETERMINANTS<br />

A permutation can also be considered as a function from the set<br />

{1, 2, ··· ,n} to {1, 2, ··· ,n}<br />

as follows. Let f (k) =i k . Permutations are of fundamental importance in certain areas<br />

of math. For example, it was by considering permutations that Galois was able to give a<br />

criterion for solution of polynomial equations by radicals, but this is a different direction<br />

than what is being attempted here.<br />

In what follows sgn will often be used rather than sgn n because the context supplies the<br />

appropriate n.<br />

3.3.2 The Definition Of The Determinant<br />

Definition 3.3.4 Let f be a real valued function which has the set of ordered lists of numbers<br />

from {1, ··· ,n} as its domain. Define<br />

∑<br />

f (k 1 ···k n )<br />

(k 1 ,··· ,k n )<br />

to be the sum of all the f (k 1 ···k n ) for all possible choices of ordered lists (k 1 , ··· ,k n ) of<br />

numbers of {1, ··· ,n} . For example,<br />

∑<br />

f (k 1 ,k 2 )=f (1, 2) + f (2, 1) + f (1, 1) + f (2, 2) .<br />

(k 1 ,k 2 )<br />

Definition 3.3.5 Let (a ij )=A denote an n × n matrix. The determinant of A, denoted<br />

by det (A) is defined by<br />

det (A) ≡<br />

∑<br />

sgn (k 1 , ··· ,k n ) a 1k1 ···a nkn<br />

(k 1,··· ,k n)<br />

where the sum is taken over all ordered lists of numbers from {1, ··· ,n}. Note it suffices to<br />

take the sum over only those ordered lists in which there are no repeats because if there are,<br />

sgn (k 1 , ··· ,k n )=0and so that term contributes 0 to the sum.<br />

Let A be an n × n matrix A =(a ij )andlet(r 1 , ··· ,r n ) denote an ordered list of n<br />

numbers from {1, ··· ,n}. LetA (r 1 , ··· ,r n ) denote the matrix whose k th row is the r k row<br />

of the matrix A. Thus<br />

det (A (r 1 , ··· ,r n )) =<br />

∑<br />

sgn (k 1 , ··· ,k n ) a r1k 1<br />

···a rnk n<br />

(3.7)<br />

and A (1, ··· ,n)=A.<br />

(k 1 ,··· ,k n )<br />

Proposition 3.3.6 Let (r 1 , ··· ,r n ) be an ordered list of numbers from {1, ··· ,n}. Then<br />

sgn (r 1 , ··· ,r n )det(A) =<br />

∑<br />

(k 1 ,··· ,k n )<br />

Proof: Let (1, ··· ,n)=(1, ··· ,r,···s, ··· ,n)sor

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