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Linear Algebra, Theory And Applications, 2012a

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240 LINEAR TRANSFORMATIONS<br />

linear transformation which is obtained as a composition of the three just described? By<br />

Theorem 9.3.17, this matrix equals the product of these three,<br />

M 3 (φ, θ, ψ) M 2 (φ, θ) M 1 (φ) .<br />

I leave the details to you. There are procedures due to Lagrange which will allow you to<br />

write differential equations for the Euler angles in a rotating body. To give an idea how<br />

these angles apply, consider the following picture.<br />

x 3<br />

x 3 (t)<br />

❘ ψ<br />

θ<br />

x 2<br />

φ<br />

x 1<br />

line of nodes<br />

This is as far as I will go on this topic. The point is, it is possible to give a systematic<br />

description in terms of matrix multiplication of a very elaborate geometrical description of<br />

a composition of linear transformations. You see from the picture it is possible to describe<br />

the motion of the spinning top shown in terms of these Euler angles.<br />

9.4 Eigenvalues <strong>And</strong> Eigenvectors Of <strong>Linear</strong> Transformations<br />

Let V be a finite dimensional vector space. For example, it could be a subspace of C n or R n .<br />

Also suppose A ∈L(V,V ) .<br />

Definition 9.4.1 The characteristic polynomial of A is defined as q (λ) ≡ det (λI − A) .<br />

The zeros of q (λ) in C are called the eigenvalues of A.<br />

Lemma 9.4.2 When λ is an eigenvalue of A whichisalsoinF, the field of scalars, then<br />

there exists v ≠0such that Av = λv.<br />

Proof: This follows from Theorem 9.3.16. Since λ ∈ F,<br />

λI − A ∈L(V,V )<br />

and since it has zero determinant, it is not one to one. <br />

The following lemma gives the existence of something called the minimal polynomial.<br />

Lemma 9.4.3 Let A ∈L(V,V ) where V is a finite dimensional vector space of dimension<br />

n with arbitrary field of scalars. Then there exists a unique polynomial of the form<br />

p (λ) =λ m + c m−1 λ m−1 + ···+ c 1 λ + c 0

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