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Linear Algebra, Theory And Applications, 2012a

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<strong>Linear</strong> Transformations<br />

Canonical Forms<br />

10.1 A Theorem Of Sylvester, Direct Sums<br />

The notation is defined as follows.<br />

Definition 10.1.1 Let L ∈L(V,W) . Then ker (L) ≡{v ∈ V : Lv =0} .<br />

Lemma 10.1.2 Whenever L ∈L(V,W) , ker (L) is a subspace.<br />

Proof: If a, b are scalars and v,w are in ker (L) , then<br />

L (av + bw) =aL (v)+bL (w) =0+0=0<br />

Suppose now that A ∈L(V,W) andB ∈L(W, U)whereV,W,U are all finite dimensional<br />

vector spaces. Then it is interesting to consider ker (BA). The following theorem of<br />

Sylvester is a very useful and important result.<br />

Theorem 10.1.3 Let A ∈L(V,W) and B ∈L(W, U) where V,W,U are all vector spaces<br />

over a field F. Suppose also that ker (A) and A (ker (BA)) are finite dimensional subspaces.<br />

Then<br />

dim (ker (BA)) ≤ dim (ker (B)) + dim (ker (A)) .<br />

Proof: If x ∈ ker (BA) , then Ax ∈ ker (B)andsoA (ker (BA)) ⊆ ker (B) . The following<br />

picture may help.<br />

ker(BA)<br />

ker(A)<br />

A<br />

✲<br />

ker(B)<br />

A(ker(BA))<br />

Now let {x 1 , ··· ,x n } be a basis of ker (A) and let {Ay 1 , ··· ,Ay m } be a basis for<br />

A (ker (BA)) . Take any z ∈ ker (BA) . Then Az = ∑ m<br />

i=1 a iAy i and so<br />

(<br />

)<br />

m∑<br />

A z − a i y i = 0<br />

which means z − ∑ m<br />

i=1 a iy i ∈ ker (A) and so there are scalars b i such that<br />

m∑<br />

n∑<br />

z − a i y i = b i x i .<br />

i=1<br />

i=1 j=1<br />

245

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