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Timothy A. Philpot - Mechanics of materials _ an integrated learning system-John Wiley (2017)

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Limit States

LRFD is based on a limit states philosophy. In this context, the term limit state is used to

describe a condition under which a structure or some portion of the structure ceases to

perform its intended function. Two general kinds of limit states apply to structures:

strength limit states and serviceability limit states. Strength limit states define safety

with regard to extreme load events during which the overriding concern is the protection

of human life from sudden or catastrophic structural failure. Serviceability limit states

pertain to the satisfactory performance of structures under ordinary load conditions. These

limit states include considerations such as excessive deflections, vibrations, cracking, and

other concerns that may have functional or economic consequences but do not threaten

public safety.

81

LOAd ANd RESISTANCE

FACTOR dESIgN

ExAMpLE 4.3

A rectangular steel plate is subjected to an axial dead load of 30 kips and a live load of

48 kips. The yield strength of the steel is 36 ksi.

(a) ASD Method: If a factor of safety of 1.5 with respect to yielding is required,

determine the required cross-sectional area of the plate according to the ASD

method.

(b) LRFD Method: Use the LRFD method to determine the required cross-sectional area

of the plate on the basis of yielding of the gross section. Use a resistance factor φ t =

0.9 and load factors of 1.2 and 1.6 for the dead and live loads, respectively.

Plan the Solution

A simple design problem illustrates how the two methods are used.

SOLUTION

(a) ASD Method

Determine the allowable normal stress from the specified yield stress and the factor of

safety:

σ

allow

σ Y 36 ksi

= = = 24 ksi

FS 1.5

The service load acting on the tension member is the sum of the dead and live compo nents:

P = D + L = 30 kips + 48 kips = 78 kips

The cross-sectional area required to support the service load is computed as

P 78 kips

2

A ≥ = = 3.25 in.

Ans.

σ 24 ksi

allow

(b) LRFD Method

The factored load acting on the tension member is computed as

P = 1.2D + 1.6L

= 1.2(30 kips) + 1.6(48 kips) = 112.8 kips

u

The nominal strength of the tension member is the product of the yield stress and the

cross-sectional area:

P

n

= σ A

Y

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