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Timothy A. Philpot - Mechanics of materials _ an integrated learning system-John Wiley (2017)

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Plan the Solution

Consider a free-body diagram (FBD) of flange B, and write the equilibrium equation

for the sum of forces in the x direction. This equation will have three unknowns: F 1 ,

F 2 , and P.

Determine the geometry-of-deformation equation and write the force–deformation relationships

for members (1) and (2). Substitute the force–deformation relationships into the

geometry-of-deformation equation to obtain the compatibility equation. Then, use the

allowable stress and area of member (1) to compute a value for P. Repeat this procedure,

using the allowable stress and area of member (2), to compute a second value for P. Choose

the smaller of these two values as the maximum

force P that can be applied to flange B.

SOLUTION

Step 1 — Equilibrium Equations: The

F 1 (1) (2)

F 2

free-body diagram for joint B is shown.

C

A

B

Notice that internal tensile forces are

— P

2

assumed in both member (1) and member

(2) [even though one would expect

to find that member (1) would actually be in compression].

The equilibrium equation for joint B is simply

∑ Fx = F2 − F1

− P = 0

(a)

Step 2 — Geometry of Deformation: Since the compound axial member is attached

to rigid supports at A and C, the overall deformation of the structure must be zero. In

other words,

δ1 + δ2

= 0

(b)

Step 3 — Force–Deformation Relationships: Write generic force–deformation

relationships for the members:

FL 1 1

FL 2 2

δ1

= and δ2

=

(c)

AE 1 1

AE 2 2

Step 4 — compatibility Equation: Substitute Equations (c) into Equation (b) to obtain

the compatibility equation:

FL 1 1 FL 2 2

+ = 0

(d)

AE 1 1 AE 2 2

Step 5 — Solve the Equations: First, we will substitute for F 2 in Equation (a). To

accomplish this, solve Equation (d) for F 2 :

F F L 1 A2

E2

2 =− 1

(e)

L2

A1

E1

Now substitute Equation (e) into Equation (a) to obtain

F L 1 A2

E2

F F L 1 A2

E2

− 1 − 1 =− 1 + 1 P

L2

A1

E

1

⎣ L2

A1

E

1 ⎦

=

— P

2

109

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