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Timothy A. Philpot - Mechanics of materials _ an integrated learning system-John Wiley (2017)

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36 kN

V

y

M

z

x

Shear Stress Formula

The maximum vertical shear stress in this pipe occurs along the intersection of the

y–z plane and the pipe wall. Note that the y–z plane is perpendicular to the direction

of the shear force V, which acts in the x direction in this instance. The thickness t

upon which the shear stress acts is equal to t = D - d = 20 mm. The maximum shear

stress on this plane is computed from the shear stress formula:

3

VQ (36,000 N)(220,667 mm )

τ max = = = 10.90 MPa Ans.

4

It (36,450,329 mm )(20 mm)

z

Pipe free-body diagram.

τ

τ

Compressive

normal stress

Stresses acting on the right

half of the pipe.

Further Explanation

At first, it may be difficult for the student to visualize the shear stress acting in a

pipe shape. To better understand the cause of shear stress in this situation, consider

a free-body diagram of a short portion of the pipe near the point of application of

the load. The 36 kN external load produces an internal bending moment M, which

produces tensile and compressive normal stresses on the -x and +x portions of the

pipe, respectively. We will investigate the equilibrium of half of the pipe.

Compressive normal stresses are created in the right half-pipe by the internal

bending moment M. Equilibrium in the y direction requires a resultant force acting

downward to resist the upward force created by the compressive normal stresses.

This downward resultant force comes from shear stresses acting vertically in the

wall of the pipe. For the example considered here, the shear stress has a magnitude

of τ = 10.90 MPa.

ExAmpLE 9.4

y

56 mm

2,000 N 3 mm

y

A cantilever beam is subjected to a concentrated

load of 2,000 N. The cross-sectional dimensions

of the double-tee shape are shown. Determine

z

x

z

K

H

5 mm

17 mm

3 mm 20 mm 3 mm

42 mm

(a) the shear stress at point H, which is located

17 mm below the centroid of the double-tee

shape.

(b) the shear stress at point K, which is located

5 mm above the centroid of the double-tee

shape.

(c) the maximum horizontal shear stress in the

double-tee shape.

15 mm

30 mm

z

56 mm

K

y

H

5 mm

17 mm

3 mm 20 mm 3 mm

3 mm

42 mm

Plan the Solution

The shear stress in the double-tee shape can be determined from the shear stress

formula [Equation (9.2)]. The challenge in this problem lies in determining the

appropriate values of Q for each calculation.

SolutioN

Section Properties

The centroid location for the double-tee cross section must be determined at the

outset. The results are shown in the accompanying figure. The moment of inertia

of the cross section about the z centroidal axis is I z = 88,200 mm 4 .

340

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